dy Given a first order linear ODE in standard form +p(1)y=g(1). To find the solution to this DE, an integrating factor µ(t)=√p(1) is used to multiply both sides of the equation so that the left hand side of the equation is transformed into a derivative of a product (µ(1)y(t))' dt Given y' + 2ty = 2te-2, p (1) = 2t and hence the integrating factor is µ (1) = √2 ore ¹². O True O False
dy Given a first order linear ODE in standard form +p(1)y=g(1). To find the solution to this DE, an integrating factor µ(t)=√p(1) is used to multiply both sides of the equation so that the left hand side of the equation is transformed into a derivative of a product (µ(1)y(t))' dt Given y' + 2ty = 2te-2, p (1) = 2t and hence the integrating factor is µ (1) = √2 ore ¹². O True O False
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![dy
Given a first order linear ODE in standard form
- +p (1)y=g (1). To find the solution to this DE, an integrating factor µ (1) = ep (1) d is used to multiply both sides of the equation so that the left hand side of the equation is transformed into a derivative of a product (µ (1) y(1))'.
dt
Given y' + 2ty = 2te
O True
O False
-21
2. p(1)=21 and hence the integrating factor is µ (1) = √21dt
ore ¹².](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa269851b-0d99-46d6-8bf5-d3daede37683%2Fba73424e-7883-4066-b18b-0b920ad0b27a%2Fe8djz7_processed.png&w=3840&q=75)
Transcribed Image Text:dy
Given a first order linear ODE in standard form
- +p (1)y=g (1). To find the solution to this DE, an integrating factor µ (1) = ep (1) d is used to multiply both sides of the equation so that the left hand side of the equation is transformed into a derivative of a product (µ (1) y(1))'.
dt
Given y' + 2ty = 2te
O True
O False
-21
2. p(1)=21 and hence the integrating factor is µ (1) = √21dt
ore ¹².
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