(X1, Y1, Z1) + (x2, Y2, z2) = (x1 + x2 + 3, Y1 + Y2 + 3, z1 + z2 + 3) с (x, у, z) %3D (сх, су, с2) (c) O The set is a vector space. O The set is not a vector space because the additive identity property is not satisfied. O The set is not a vector space because the additive inverse property is not satisfied. The set is not a vector space because it is not closed under scalar multiplication. O The set is not a vector space because the distributive property is not satisfied.

Q: find 3x2 + 2y = 5, 2x2 + 3y = 10.

A:

Q: %3D +29-2X -34 %3D

A:

Q: T+9/2= 7t-6/14

A: Given query is to find the value of T.

Q: -7=2r+1

A: Given,     -7 = 2r + 1         ⇒  2r = -7 -1         ⇒   2r = -8        ⇒     r =  -82

Q: x2+9x=-14

A: Given equation is x2+9x=-14 The equation can be solved by splitting the middle term.…

Q: Evaluate 2x - 3xy + 5y for x= -3 and y = 6

A:

Q: Evaluate x2 + 5x, for x = 6.

A: x2+5x, x=6

Q: 3x + 4y = 19 3x + 6y = 33

A:

Q: Find a4 when a1 = 3 and r = - 2

A:

Q: -8=-4+v

A: The given equation is,

Q: Simplify (8a power 3 bpower2 c power 0)

A:

Q: Find 6x+y, when x=1 and y=7

A: Given: Find 6x+y, when x=1 and y=7

Q: Evaluate x2 - 6x + 3, for x = 7

A: We have to evaluate x2-6x+3 for x=7. Let Px=x2-6x+3 Now, at x=7 P7=72-6·7+3=49-42+3=52-42=10

Q: Evaluate 2x2 +1+2/ dr.

A: First we distribute the x and write using exponents.

Q: Evaluate (4r +1) dr -2

A:

Q: x2+9x=-14

A:

Q: evaluate 9=4x-1 when y=19

A: Evaluate 9=4x-1 when y=19

Q: t 2X +3 x² イー

A: Simplify the above expression.

Q: Simplify (5x/y4)-2

A: Given, 5xy4-2

Q: 2x+5+7=

A: First, combine the numerical terms 5 and 7. 2x+5+7=2x+12=2x+2·6