dx 19) u = 4x + 9 4x +9 1 A) B) 2/4x + 9 + C + C + 9)3/2 1 + C V4x + 9 C) 2- S dx 20) u == 4x + 6 4x + 6 1 A) 4(4x + 6)3/2 B) 2/4x + 6 + C + C 1 |4x + 6 + C D) 2– + C V4x + 6 Solve the initial value problem. 21) dy (2x2), y(0) = 11 = x COS A) y = u sin (u) B) y = sin (2x2) + + 11 C) y = sin(2x2) + 11 - sin(2x2) + 11 2 D) y =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 27RE
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### Calculus Problems and Solutions

#### Integration Problems:

**19) Solve the integral:**

\[
\int \frac{dx}{\sqrt{4x+9}}, \quad u = 4x + 9
\]

Options:
- A) \(\frac{1}{4(4x+9)^{3/2}} + C\)
- B) \(2\sqrt{4x+9} + C\)
- C) \(\frac{1}{\sqrt{4x+9}} + C\)
- D) \(\frac{1}{2\sqrt{4x+9}} + C\)

**20) Solve the integral:**

\[
\int \frac{dx}{\sqrt{4x+6}}, \quad u = 4x + 6
\]

Options:
- A) \(\frac{1}{4(4x+6)^{3/2}} + C\)
- B) \(2\sqrt{4x+6} + C\)
- C) \(\frac{1}{\sqrt{4x+6}} + C\)
- D) \(\frac{1}{2\sqrt{4x+6}} + C\)

#### Differential Equations:

**21) Solve the initial value problem:**

\[
\frac{dy}{dx} = x \cos(2x^2), \quad y(0) = 11
\]

Options:
- A) \(y = \frac{1}{u} \sin(u)\)
- B) \(y = \sin(2x^2) + 11\)
- C) \(y = \frac{1}{4} \sin(2x^2) + 11\)
- D) \(y = \frac{x^2}{2} \sin(2x^2) + 11\)

**22) Solve the initial value problem:**

\[
\frac{dy}{dx} = 18(6x-2)^{-4}, \quad y(0) = 1
\]

Options:
- A) \(y = -\frac{3}{5}(6x-2)^{-5} + 0.981\)
- B) \(y = - (6x-2)^{-3} + 0.875\)
- C) \(
Transcribed Image Text:### Calculus Problems and Solutions #### Integration Problems: **19) Solve the integral:** \[ \int \frac{dx}{\sqrt{4x+9}}, \quad u = 4x + 9 \] Options: - A) \(\frac{1}{4(4x+9)^{3/2}} + C\) - B) \(2\sqrt{4x+9} + C\) - C) \(\frac{1}{\sqrt{4x+9}} + C\) - D) \(\frac{1}{2\sqrt{4x+9}} + C\) **20) Solve the integral:** \[ \int \frac{dx}{\sqrt{4x+6}}, \quad u = 4x + 6 \] Options: - A) \(\frac{1}{4(4x+6)^{3/2}} + C\) - B) \(2\sqrt{4x+6} + C\) - C) \(\frac{1}{\sqrt{4x+6}} + C\) - D) \(\frac{1}{2\sqrt{4x+6}} + C\) #### Differential Equations: **21) Solve the initial value problem:** \[ \frac{dy}{dx} = x \cos(2x^2), \quad y(0) = 11 \] Options: - A) \(y = \frac{1}{u} \sin(u)\) - B) \(y = \sin(2x^2) + 11\) - C) \(y = \frac{1}{4} \sin(2x^2) + 11\) - D) \(y = \frac{x^2}{2} \sin(2x^2) + 11\) **22) Solve the initial value problem:** \[ \frac{dy}{dx} = 18(6x-2)^{-4}, \quad y(0) = 1 \] Options: - A) \(y = -\frac{3}{5}(6x-2)^{-5} + 0.981\) - B) \(y = - (6x-2)^{-3} + 0.875\) - C) \(
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