Using [ y = e^(2x) (c1 + c2) + 3/2x2 (2x) ] and [ y = ( c1 + c2x ) e^(2x) + 3x/25 sinx + 4x/25 cnx + 4/125 sinx + 22/125 cos2x]   Solve: y'' - 4y' + 4y = 3e^(2x) + xsinx   Show work written and clearly please

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Using [ y = e^(2x) (c1 + c2) + 3/2x2 (2x) ] and [ y = ( c1 + c2x ) e^(2x) + 3x/25 sinx + 4x/25 cnx + 4/125 sinx + 22/125 cos2x]

 

Solve: y'' - 4y' + 4y = 3e^(2x) + xsinx

 

Show work written and clearly please

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