During the tensile test, experiment on a sample of mild steel, data represented in thefigure below was obtained with an initial diameter (do) of 0.505 inch. At failure, thereduced diameter (d;) of the sample was 0.305 inch. Gauge Length (Lo) is 2 inchesand final Gauge Length (L) is 2.625 inches. Answer the questions below:UsTR70-60 -LoLyP*IR50 -ELPL: proportimal limitEL Elastic limitUXP = 4pper yield pointLyp : Lowerus : uiti mated streagthIR : Indicanteed StrengtyRuptureTR: True strength Ruptue40AL or 8tP30**PL (proportimal limt)Direct strainE strain (in/in)aStress Iblinz (esi)0.003.ogoo-200 2. Young'sModulusevaluateselasticitywithin theregion from:(а) 0 -ProportionalLimit. (b)ProportionalLimit - Loweryield Point.(c) Loweryield Point -Truestrength.

Stress-strain diagram illustrates the relation between stress acting and strain on a material due to…

During the tensile test, experiment on a sample of mild steel, data represented in the figure below was obtained with an initial diameter (do) of 0.505 inch. At failure, the reduced diameter (d;) of the sample was 0.305 inch. Gauge Length (Lo) is 2 inches and final Gauge Length (L,) is 2.625 inches. Answer the questions below:

During the tensile test, experiment on a sample of mild steel, data represented in the figure below was obtained with an initial diameter (do) of 0.505 inch. At failure, the reduced diameter (d;) of the sample was 0.305 inch. Gauge Length (Lo) is 2 inches and final Gauge Length (L,) is 2.625 inches. Answer the questions below:

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A tensile test specimen of aluminum alloy having a diameter of 0.5 in. and a gage length of 2 in. was tested to fracture. The complete stress-strain diagram for this specimen is shown below to the left. The small strain portion of this diagram has been enlarged (to the right) to show in more detail the linear portion of the stress-strain diagram. Determine (a) Young's modulus or modulus of elasticity (i.e., the slope of linear portion), (b) yield stress (using the so-called 0.2% offset method from the lecture notes), (c) yield strain (i.e., the strain corresponding to yield stress, not the 0.2%!), (d) ultimate strength (i.e., the peak in stress-strain diagram), (e) rupture stress (i.e., stress at breaking/failure), (f) rupture strain (i.e., the strain corresponding to rupture stress). 80 70 70 60 60 50 50 40 30 30 20 20 10 10 0.005 0.01 0.015 0.02 Strain (in/in) Strain (in/in) Stress (ksi) 0.015 - 0.03 - 0.12 - 0.135 - 0.15 Stress (ksi)
In a tensile test, Load and Elongation are Normalized to Engineering Stress and Engineering Strain . Why?
A cylindrical metal specimen having an original diameter of 10.63 mm and gauge length of 50.1 mm is pulled in tension until fracture occurs. The diameter at the point of fracture is 7.60 mm, and the fractured gauge length is 74.5 mm. Calculate the ductility in terms of (a) percent reduction in area (percent RA), and (b) percent elongation (percent EL). (a) i percent RA (b) i percent EL
In a tensile test for an aluminum alloy, the sample used is 2 inches long and 0.5 inches in diameter. The proportional portion of the tension stress-strain diagram for an aluminum alloy is shown below. Determine the modulus of elasticity for this material: ____x106 lb/in2. Pay attention to units and calculate your answer to 1 decimal place for the unit specified above.
th
I need typing answer urgent
1. The following data were obtained during a tension test of an aluminum alloy. The initial diameter of the test specimen was 0.505 in. and the gage length was 2.0 in. Load (lb) 0 2 310 4 640 6 950 9 290 11 600 12 600 Elongation (in.) 0.00220 0.00440 0.00660 0.00880 0.0110 0.0150 Load (lb) 14 000 14 400 14 500 14 600 14 800 14 600 13 600 Elongation (in.) 0.020 0.025 0.060 0.080 0.100 0.120 Fracture Plot the stress-strain diagram and determine the following mechanical properties: (a) proportional limit; (b) modulus of elasticity; (c) yield point; (d) yield strength at 0.2% offset; (e) ultimate strength; and (f) rupture strength.
The stainless steel specimen is shown in Figure 3 with tensile engineering stress-strain behaviour. a)Compute the modulus of elasticity. and Compute the yield strength at a strain offset of 0.002.
(b) (i) A tensile test specimen made from 0.4% C steel has a circular cross section of diameter d mm and a gauge length of 25 mm. When a load of 4500 N is applied during the test, the gauge length of the specimen extends to 25.02 mm. If the Young's Modulus of the steel is 199 GPa, calculate the diameter of the tensile test specimen used. 4
Please answer d,e,f
I5 In a tensile test experiment of carbon steel. a standard specimen (D= 0.505 in. Gauge length=2.0 in & total length 8 in) had a 0.2% offset yield strength of 80.000 psi and engineering strain of 0.010 at the yield strength point Calculate: The load (force) at this point. The instantaneous area of the specimen at this point. c. The true stress at this point. d. The true strain at this point. e. The total length of the specimen. if the load is released at this point.
During a tension test, measurements for the applied load and the corresponding elongation are taken at frequent intervals. These data points are then used to: a. calculate the stress caused by the applied load at each data point. b. calculate the strain in the specimen induced by the applied load at each data point. c. plot a stress-strain diagram. d. all of the above