Problem NO. 2. A student performed a tensile test in one of his samples, an aluminum specimen which is 0.505 inches in diameter, length L of 2 inches. A) Calculate the value of E when the load is increased by an amount of P 2 kips, and the distance between gage marks increases by an amount of AL = 0.00196 inch. B) What is the value of E if the proportional limit stress for this specimen is oPL = 45 ksi? 2 in. 0 505 in.
Problem NO. 2. A student performed a tensile test in one of his samples, an aluminum specimen which is 0.505 inches in diameter, length L of 2 inches. A) Calculate the value of E when the load is increased by an amount of P 2 kips, and the distance between gage marks increases by an amount of AL = 0.00196 inch. B) What is the value of E if the proportional limit stress for this specimen is oPL = 45 ksi? 2 in. 0 505 in.
Steel Design (Activate Learning with these NEW titles from Engineering!)
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Author:Segui, William T.
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Chapter1: Introduction
Section: Chapter Questions
Problem 1.5.6P: The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular...
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![Problem NO. 2. A student performed a tensile test in one of his samples, an aluminum
specimen which is 0.505 inches in diameter, length L of 2 inches. A) Calculate the
value of E when the load is increased by an amount of P 2 kips, and the distance
between gage marks increases by an amount of AL = 0.00196 inch. B) What is the
value of E if the proportional limit stress for this specimen is OPL = 45 ksi?
2 in.
0 505 in.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ef6b65f-5d8d-4b0b-a686-ecf7b6a89a1b%2F378c4f86-5969-48b5-9f2e-c8f11b2d8111%2Fa9slpn8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem NO. 2. A student performed a tensile test in one of his samples, an aluminum
specimen which is 0.505 inches in diameter, length L of 2 inches. A) Calculate the
value of E when the load is increased by an amount of P 2 kips, and the distance
between gage marks increases by an amount of AL = 0.00196 inch. B) What is the
value of E if the proportional limit stress for this specimen is OPL = 45 ksi?
2 in.
0 505 in.
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