During hydrogenation, cis double bonds are converted to trans double bonds. In the lab, we compare three fats, each of which has fatty acid chains that are exactly the same length (number of carbons) and observe the following: Fat 1 contains only saturated fatty acids 16 carbons long, and has a melting point of 65 degrees C. Fat 2 contains only cis unsaturated fatty acids 16 carbons long, and has a melting point of 35 degrees C. Fat 3 contains only trans fatty acids 16 carbons long, and has a melting point of 65 degrees C. Both Fat 2 and Fat 3 contain fatty acids with a single double bond; fat 1 has no double bonds. Why do Fat 3 and Fat 1 have more similar melting points than Fat 3 and Fat 2? Group of answer choices The number of hydrogen atoms in the fatty acids of fats 1 & 3 is higher, and having more hydrogen atoms raises the melting point of the fat. The fatty acids in fats 1 & 3 have a linear shape, so they pack tightly together and have lots of hydrophobic interactions, raising their melting point compared to fat 2, which has bent fatty acids. The fatty acids in fats 1 & 3 have greater chemical stability and are harder to break down than the fatty acids in fat 2, which raises their melting point. Fats 1 & 3 have more cholesterol, which raises their melting point compared to fat 2, which does not have much cholesterol.

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
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During hydrogenation, cis double bonds are converted to trans double bonds.  In the lab, we compare three fats, each of which has fatty acid chains that are exactly the same length (number of carbons) and observe the following:

  • Fat 1 contains only saturated fatty acids 16 carbons long, and has a melting point of 65 degrees C.
  • Fat 2 contains only cis unsaturated fatty acids 16 carbons long, and has a melting point of 35 degrees C.
  • Fat 3 contains only trans fatty acids 16 carbons long, and has a melting point of 65 degrees C.

Both Fat 2 and Fat 3 contain fatty acids with a single double bond; fat 1 has no double bonds.  Why do Fat 3 and Fat 1 have more similar melting points than Fat 3 and Fat 2?

Group of answer choices

The number of hydrogen atoms in the fatty acids of fats 1 & 3 is higher, and having more hydrogen atoms raises the melting point of the fat.

The fatty acids in fats 1 & 3 have a linear shape, so they pack tightly together and have lots of hydrophobic interactions, raising their melting point compared to fat 2, which has bent fatty acids.
The fatty acids in fats 1 & 3 have greater chemical stability and are harder to break down than the fatty acids in fat 2, which raises their melting point.
Fats 1 & 3 have more cholesterol, which raises their melting point compared to fat 2, which does not have much cholesterol.
**Question:**

Which of the following would be **UNABLE** to pass freely through a pure phospholipid bilayer (one that lacks any transport proteins)? Choose all correct answers.

**Options and Diagrams:**

1. **Fructose Molecule:**
   - A hexagonal ring structure with various hydroxyl (OH) groups attached, indicating it is a simple sugar.

2. **Sodium Ion (Na+):**
   - Shown as a positively charged ion with a plus sign (+) and a simple representation of its electron arrangement.

3. **Chloride Ion (Cl-):**
   - Depicted as a negatively charged ion with a minus sign (-) and a corresponding arrangement of electrons surrounding it.

4. **Oxygen Molecule (O₂):**
   - Illustrated as two oxygen atoms connected by a double bond, with shared electrons marked around the outside.

5. **Steroid Molecule:**
   - Represented by a complex structure consisting of four fused rings, characteristic of steroid compounds.

**Answer Choices:**

- ☐ Sodium ion
- ☐ Oxygen molecule
- ☐ Fructose molecule
- ☐ Steroid molecule
- ☐ Chloride ion
Transcribed Image Text:**Question:** Which of the following would be **UNABLE** to pass freely through a pure phospholipid bilayer (one that lacks any transport proteins)? Choose all correct answers. **Options and Diagrams:** 1. **Fructose Molecule:** - A hexagonal ring structure with various hydroxyl (OH) groups attached, indicating it is a simple sugar. 2. **Sodium Ion (Na+):** - Shown as a positively charged ion with a plus sign (+) and a simple representation of its electron arrangement. 3. **Chloride Ion (Cl-):** - Depicted as a negatively charged ion with a minus sign (-) and a corresponding arrangement of electrons surrounding it. 4. **Oxygen Molecule (O₂):** - Illustrated as two oxygen atoms connected by a double bond, with shared electrons marked around the outside. 5. **Steroid Molecule:** - Represented by a complex structure consisting of four fused rings, characteristic of steroid compounds. **Answer Choices:** - ☐ Sodium ion - ☐ Oxygen molecule - ☐ Fructose molecule - ☐ Steroid molecule - ☐ Chloride ion
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