Due to the application of a surcharge of g=1.8 ton/m³ and height o 7dry = 1.7 t/m³ w = 20% Sand 4 m e = 0.7 =2 t/m3 7 sat G= 2.7 Pc= 1.2 kg/cm² 6 m Cc =0.28 Cv = 1.2*10° cm? /sec -3 Clay
Due to the application of a surcharge of g=1.8 ton/m³ and height o 7dry = 1.7 t/m³ w = 20% Sand 4 m e = 0.7 =2 t/m3 7 sat G= 2.7 Pc= 1.2 kg/cm² 6 m Cc =0.28 Cv = 1.2*10° cm? /sec -3 Clay
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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