ds S dt k+S where S= substrate concentration (moles/L), Vm = maximum uptake rate (moles/L/d), and k, = the half- saturation constant, which is the substrate level at which uptake is half of the maximum [moles/L]. If the initial substrate level at t = 0 is So, this differential equation can be solved for S = S, – v„t +k, In(S, / S) f(S) = S, – V, t+ k In (S, /S)– S Determining the root of f(S) where So = 8 moles/L, Vm= 0.7 moles/L/d, and k, = 2.5 moles/L. Iterate until ɛ< 0.1 or the number of iterations reaches 3, whichever comes first.

ds S dt k+S where S= substrate concentration (moles/L), Vm = maximum uptake rate (moles/L/d), and k, = the half- saturation constant, which is the substrate level at which uptake is half of the maximum [moles/L]. If the initial substrate level at t = 0 is So, this differential equation can be solved for S = S, – v„t +k, In(S, / S) f(S) = S, – V, t+ k In (S, /S)– S Determining the root of f(S) where So = 8 moles/L, Vm= 0.7 moles/L/d, and k, = 2.5 moles/L. Iterate until ɛ< 0.1 or the number of iterations reaches 3, whichever comes first.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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