Dry the filter paper + AgCl(s) and weigh it. The following data is obtained : a. Mass of XCl2 : 0.2455 g b. Mass of filter paper + watch glass: 22.6541 g c. Mass of filter paper + watch glass + solid AgCl = 23.3934 g d. Mass of AgCI (s) : Calculations: Balance the above chemical equations Perform the following calculations : g of AgCl(s) --- moles of AgCl - moles of XCl, - molar mass of XCl - compare the molar mass of X with the periodic table to find the unknown element Х. -→ moles of AgCl → moles of XCI2 -→ molar mass of XC12 in g/ mole -→ molar mass of X
Dry the filter paper + AgCl(s) and weigh it. The following data is obtained : a. Mass of XCl2 : 0.2455 g b. Mass of filter paper + watch glass: 22.6541 g c. Mass of filter paper + watch glass + solid AgCl = 23.3934 g d. Mass of AgCI (s) : Calculations: Balance the above chemical equations Perform the following calculations : g of AgCl(s) --- moles of AgCl - moles of XCl, - molar mass of XCl - compare the molar mass of X with the periodic table to find the unknown element Х. -→ moles of AgCl → moles of XCI2 -→ molar mass of XC12 in g/ mole -→ molar mass of X
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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