Dry the filter paper + AgCl(s) and weigh it. The following data is obtained : a. Mass of XCl2 : 0.2455 g b. Mass of filter paper + watch glass: 22.6541 g c. Mass of filter paper + watch glass + solid AgCl = 23.3934 g d. Mass of AgCI (s) : Calculations: Balance the above chemical equations Perform the following calculations : g of AgCl(s) --- moles of AgCl - moles of XCl, - molar mass of XCl - compare the molar mass of X with the periodic table to find the unknown element Х. -→ moles of AgCl → moles of XCI2 -→ molar mass of XC12 in g/ mole -→ molar mass of X

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**Laboratory Procedure: Determining the Molar Mass of an Unknown Element**

**Apparatus Setup**
- The diagram shows a filtration setup where a solution is poured through a funnel containing filter paper, allowing the filtrate to collect in a beaker below.

**Procedure**
1. **Dry the filter paper and silver chloride (AgCl)** and weigh it.

**Data Collected:**
- Mass of XCl₂: 0.2455 g
- Mass of filter paper + watch glass: 22.6541 g
- Mass of filter paper + watch glass + solid AgCl: 23.3934 g

**Objective:**
- Determine the mass of AgCl (s).

**Calculations:**
1. **Balance the Chemical Equations**
   - Begin by balancing the relevant chemical equations that involve the formation of AgCl.

2. **Perform the Following Calculations:**
   - **Determine the moles of AgCl:**
     - Convert the mass of AgCl obtained from the difference in initial and final masses to moles using its molar mass.
     
   - **Relate moles of AgCl to moles of XCl₂:**
     - Assume a stoichiometric relationship from the balanced equation to find moles of XCl₂ from moles of AgCl.

   - **Calculate the molar mass of XCl₂ in g/mole:**
     - Use the mass and moles of XCl₂ to find its molar mass.

   - **Determine the molar mass of X:**
     - Subtract the known mass of Cl₂ from the molar mass of XCl₂ to find the molar mass of the unknown element X.

3. **Identify the Unknown Element:**
   - Compare the calculated molar mass of X with values on the periodic table to identify the unknown element.
Transcribed Image Text:**Laboratory Procedure: Determining the Molar Mass of an Unknown Element** **Apparatus Setup** - The diagram shows a filtration setup where a solution is poured through a funnel containing filter paper, allowing the filtrate to collect in a beaker below. **Procedure** 1. **Dry the filter paper and silver chloride (AgCl)** and weigh it. **Data Collected:** - Mass of XCl₂: 0.2455 g - Mass of filter paper + watch glass: 22.6541 g - Mass of filter paper + watch glass + solid AgCl: 23.3934 g **Objective:** - Determine the mass of AgCl (s). **Calculations:** 1. **Balance the Chemical Equations** - Begin by balancing the relevant chemical equations that involve the formation of AgCl. 2. **Perform the Following Calculations:** - **Determine the moles of AgCl:** - Convert the mass of AgCl obtained from the difference in initial and final masses to moles using its molar mass. - **Relate moles of AgCl to moles of XCl₂:** - Assume a stoichiometric relationship from the balanced equation to find moles of XCl₂ from moles of AgCl. - **Calculate the molar mass of XCl₂ in g/mole:** - Use the mass and moles of XCl₂ to find its molar mass. - **Determine the molar mass of X:** - Subtract the known mass of Cl₂ from the molar mass of XCl₂ to find the molar mass of the unknown element X. 3. **Identify the Unknown Element:** - Compare the calculated molar mass of X with values on the periodic table to identify the unknown element.
**Determination of an Unknown Element X by the Following Stoichiometry Reaction:**

\[ \text{XCl}_2 \, (\text{aq}) + \text{AgNO}_3 \, (\text{aq}) \rightarrow \text{AgCl} \, (\text{s}) + \text{X(NO}_3)_2 \]

**Procedure and Data:**

1. Weigh a piece of weighing paper and tare the balance. Then add 0.2455 g of XCl\(_2\).
2. Transfer the weighed XCl\(_2\) to a beaker.
3. Add 75.0 mL of 0.100 M AgNO\(_3\) aqueous solution using a graduated cylinder.
4. An AgCl white solid will form.
5. Weigh a filter paper and a watch glass, then set up the filtration according to the following diagram:

**Diagram Description:**

The diagram depicts a filtration apparatus setup. Here's the breakdown:

- A ring clamp is attached to a stand supporting a funnel.
- The funnel is placed above a conical flask to collect the filtrate.
- The entire setup is situated on a flat surface or tray to prevent spillage.

**Next Step:**

Filter the heterogeneous mixture and collect all AgCl(s) on the filter paper.
Transcribed Image Text:**Determination of an Unknown Element X by the Following Stoichiometry Reaction:** \[ \text{XCl}_2 \, (\text{aq}) + \text{AgNO}_3 \, (\text{aq}) \rightarrow \text{AgCl} \, (\text{s}) + \text{X(NO}_3)_2 \] **Procedure and Data:** 1. Weigh a piece of weighing paper and tare the balance. Then add 0.2455 g of XCl\(_2\). 2. Transfer the weighed XCl\(_2\) to a beaker. 3. Add 75.0 mL of 0.100 M AgNO\(_3\) aqueous solution using a graduated cylinder. 4. An AgCl white solid will form. 5. Weigh a filter paper and a watch glass, then set up the filtration according to the following diagram: **Diagram Description:** The diagram depicts a filtration apparatus setup. Here's the breakdown: - A ring clamp is attached to a stand supporting a funnel. - The funnel is placed above a conical flask to collect the filtrate. - The entire setup is situated on a flat surface or tray to prevent spillage. **Next Step:** Filter the heterogeneous mixture and collect all AgCl(s) on the filter paper.
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