You are given a mixture of CUCO, and CuO. You place the mixture in a crucible and heat it to decompose the CUCO; into CO, gas and CuO. You made sure that the CUCO, had completely decomposed by constantly heating it, cooling it, and weighing it until the mass remains the same. Using the data below from the experiment, calculate the % CUCO, in the original sample. Mass of empty crucible: 22.107 g Mass of crucible + sample before heating: 23.152 g Mass of crucible + sample at constant mass: 22.845 g Please do not include units in your answer and use proper sig figs. Assume that all of the given values have 3 digits after the decimal (even if Canvas drops the zero at the end).

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You are given a mixturc of CUCO, and CuO. You place the mixturcina crucible and heat it to
decompose the CUCO; into CO, gas and CuO. You made sure that the CUCO, had completely
decomposed by constantly heating it, cooling it, and weighing it until the mass remains the same.
Using the data below from the experiment, calculate the % CUCO; in the original sample.
Mass of empty crucible: 22.107 g
Mass of crucible + sample beforc heating: 23.152 g
Mass of crucible + sample at constant mass: 22.845g
Please do not include units in your answer and use proper sig figs. Assume that all of the given values have
3 digits after the decimal (even if Canvas drops the zero at the end).
Transcribed Image Text:You are given a mixturc of CUCO, and CuO. You place the mixturcina crucible and heat it to decompose the CUCO; into CO, gas and CuO. You made sure that the CUCO, had completely decomposed by constantly heating it, cooling it, and weighing it until the mass remains the same. Using the data below from the experiment, calculate the % CUCO; in the original sample. Mass of empty crucible: 22.107 g Mass of crucible + sample beforc heating: 23.152 g Mass of crucible + sample at constant mass: 22.845g Please do not include units in your answer and use proper sig figs. Assume that all of the given values have 3 digits after the decimal (even if Canvas drops the zero at the end).
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