Q3: A: What mass of AgNO3 is needed to convert 3.46g of NażCO3 to Ag2CO3, and calculate the mass of A92CO3 will be formed? Discuss your results. 2AGNO3(aq) +N22CO3(a9) → Ag:CO3(9) + 2NAN03(aq) B: Calculate the Normality of solutions containing the following with discussing your results:- 1) 8 gm /L of N22CO3 (when the CO3? reacts with two protons). 2) 9.5 gm /L of K2Cr2O7 (the Cr is reduced to Cr*³).
Q3: A: What mass of AgNO3 is needed to convert 3.46g of NażCO3 to Ag2CO3, and calculate the mass of A92CO3 will be formed? Discuss your results. 2AGNO3(aq) +N22CO3(a9) → Ag:CO3(9) + 2NAN03(aq) B: Calculate the Normality of solutions containing the following with discussing your results:- 1) 8 gm /L of N22CO3 (when the CO3? reacts with two protons). 2) 9.5 gm /L of K2Cr2O7 (the Cr is reduced to Cr*³).
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Q3: A: What mass of AgNO3 is needed to convert 3.46g of Na2CO3 to Ag2CO3, and calculate
the mass of A92CO3 will be formed? Discuss your results.
2AGNO3(aq) +Na2CO3(aq) → Ag2CO3(e) + 2NaNo3(aq)
B: Calculate the Normality of solutions containing the following with discussing your
results:-
1) 8 gm /L of Na2CO3 (when the CO3² reacts with two protons).
2) 9.5 gm /L of K2CR2O7 (the Cr is reduced to Cr*3).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F842a67e4-fb9f-42ef-ae42-75a44d6a24d7%2F760f4d5e-81ef-4ff9-860b-48728fac37a1%2Fd8ivx9u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q3: A: What mass of AgNO3 is needed to convert 3.46g of Na2CO3 to Ag2CO3, and calculate
the mass of A92CO3 will be formed? Discuss your results.
2AGNO3(aq) +Na2CO3(aq) → Ag2CO3(e) + 2NaNo3(aq)
B: Calculate the Normality of solutions containing the following with discussing your
results:-
1) 8 gm /L of Na2CO3 (when the CO3² reacts with two protons).
2) 9.5 gm /L of K2CR2O7 (the Cr is reduced to Cr*3).
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