Dry sand y = 16.5 kN/m³ 1.5 m Groundwater table Sand 1.5 m Ysat = 19 kN/m3 N60 :1.5 m Clay Ysat = 16.8 kN/m3 1.5 m * A•8 1.5 m 1.5 m 10 Sand Figure P3.2 Си 0.29N72 Ра (3.8) where pa = atmospheric pressure ( 100 kN/m?; - 2000 lb/in²). The overconsolidation ratio, OCR, of a natural clay deposit can also be correlated with the standard penetration number. On the basis of the regression analysis of 110 data points, Mayne and Kemper (1988) obtained the relationship N60 OCR = 0.193 0.689 (3.9) where o, = effective vertical stress in MN/m?.

Dry sand y = 16.5 kN/m³ 1.5 m Groundwater table Sand 1.5 m Ysat = 19 kN/m3 N60 :1.5 m Clay Ysat = 16.8 kN/m3 1.5 m * A•8 1.5 m 1.5 m 10 Sand Figure P3.2 Си 0.29N72 Ра (3.8) where pa = atmospheric pressure ( 100 kN/m?; - 2000 lb/in²). The overconsolidation ratio, OCR, of a natural clay deposit can also be correlated with the standard penetration number. On the basis of the regression analysis of 110 data points, Mayne and Kemper (1988) obtained the relationship N60 OCR = 0.193 0.689 (3.9) where o, = effective vertical stress in MN/m?.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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