Drug content assessment. Refer to Exercise 8.16 (p. 443) and the Analytical Chemistry (Dec. 15, 2009) study in which scientists used high-performance liquid chromatog- raphy to determine the amount of drug in a tablet. Recall that 25 tablets were produced at each of two different, independent sites. The researchers want to determine if the two sites produced drug concentrations with different vari- ances. A Minitab printout of the analysis follows. Locate the test statistic and p-value on the printout. Use these values and a = .05 to conduct the appropriate test for the researchers.
Drug content assessment. Refer to Exercise 8.16 (p. 443) and the Analytical Chemistry (Dec. 15, 2009) study in which scientists used high-performance liquid chromatog- raphy to determine the amount of drug in a tablet. Recall that 25 tablets were produced at each of two different, independent sites. The researchers want to determine if the two sites produced drug concentrations with different vari- ances. A Minitab printout of the analysis follows. Locate the test statistic and p-value on the printout. Use these values and a = .05 to conduct the appropriate test for the researchers.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question

Transcribed Image Text:8.83 Drug content assessment. Refer to Exercise 8.16 (p. 443)
and the Analytical Chemistry (Dec. 15, 2009) study in
which scientists used high-performance liquid chromatog-
HPLC
raphy to determine the amount of drug in a tablet. Recall
that 25 tablets were produced at each of two different,
independent sites. The researchers want to determine if the
two sites produced drug concentrations with different vari-
ances. A Minitab printout of the analysis follows. Locate
the test statistic and p-value on the printout. Use these
values and a = .05 to conduct the appropriate test for the
researchers.
Test and CI for Two Variances: Content vs Site
Method
o (1) / o(2) = 1
Null hypothesis
Alternative hypothesis o(1) / o(2) # 1
Significance level
a = 0.05
F method was used. This method is accurate for normal data only.
Statistics
95% CI for
site
N
StDev
Variance
StDevs
9.406
11.147
(2.395, 4.267)
(2.607, 4.645)
25
3.067
2
25 3.339
Ratio of standard deviations = 0.919
Ratio of variances = 0.844
95% Confidence Intervals
CI for StDev
Ratio
(0.610, 1.384)
CI for
Variance
Ratio
Method
F
(0.372, 1.915)
Tests
Test
DF1
DF2
Statistic
0.84
Method
P-Value
F
24
24
0.681
Expert Solution

Step 1
The aim is to test whether the two sites produced drug concentrations with different variance.
The test hypotheses are given below:
With the help of MINITAB output, the F-statistic is 0.84 and the p-value is 0.681.
Here, the level of significance is 0.05.
Step by step
Solved in 2 steps
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