Driving to Red Hook at night at 65 miles/hour, a Bard student sees a deer in the road 50 meters straight ahead, frozen in the car headlights. The student immediately slams on the breaks, decelerating (negatively accelerating) the car at a constant 8 m/s2. If the deer remains frozen in place, does the student avoid hitting the deer?
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
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straight ahead, frozen in the car headlights. The student immediately slams on the breaks,
decelerating (negatively accelerating) the car at a constant 8 m/s2. If the deer remains frozen in
place, does the student avoid hitting the deer?"
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given initial speed u=65 mi/h = 0.447 * 65 =29.055 m/s
acceleration a =-8 m/s
distance between bear and car . s = 50 m
using equation of motion v2=u2 + 2as
where v is the final speed
substituting values
v2=29.0552 - 2*8*50 =44.193
therefore final speed v =(44.193)1/2 =6.65 m/s
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