OK, this is the last time for one of these crazy adventures. THIS time, though, there is a window in the floor, and you can see that you re in a rocket which has just taken off from the surface of an alien planet. By taking careful measurements out that window you determine that the rocket is accelerating upward at 8.14 m/s^2. When you drop a ball from a height of 2.15 m, it hits the floor 0.200 s later. What is the value of g for the alien world below you?

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**Problem: Determining Gravitational Acceleration (g) on an Alien Planet**

OK, this is the last time for one of these crazy adventures. THIS time, though, there is a window in the floor, and you can see that you’re in a rocket which has just taken off from the surface of an alien planet. By taking careful measurements out that window, you determine that the rocket is accelerating upward at 8.14 m/s². When you drop a ball from a height of 2.15 meters, it hits the floor 0.200 seconds later. What is the value of g for the alien world below you?

**Analysis:**
Upon dropping the ball from a height of 2.15 meters and observing that it takes 0.200 seconds to hit the floor, we can use the kinematic equations of motion to solve for the gravitational acceleration (g) on the alien planet. We must account for the upward acceleration of the rocket while calculating the net acceleration affecting the ball’s descent.

*Given:*
- Rocket upward acceleration (a₁) = 8.14 m/s²
- Drop height (h) = 2.15 m
- Time duration (t) = 0.200 s

**Step-by-Step Solution:**
1. Identify the effective downward acceleration (a₂) affecting the ball inside the rocket.
    \[
    a₂ = g + a₁
    \]
2. Use the second kinematic equation to relate the height, time, and net acceleration:
    \[
    h = \frac{1}{2} a₂ t²
    \]
    Substituting in the known values:
    \[
    2.15 = \frac{1}{2} a₂ (0.200)²
    \]
    Solving for a₂:
    \[
    2.15 = \frac{1}{2} a₂ (0.04)
    \]
    \[
    2.15 = 0.02 a₂
    \]
    \[
    a₂ = \frac{2.15}{0.02} = 107.5 m/s²
    \]
3. Finally, solve for the value of g:
    \[
    g = a₂ - a₁
    \]
    \[
    g = 107.5 - 8.14 =
Transcribed Image Text:**Problem: Determining Gravitational Acceleration (g) on an Alien Planet** OK, this is the last time for one of these crazy adventures. THIS time, though, there is a window in the floor, and you can see that you’re in a rocket which has just taken off from the surface of an alien planet. By taking careful measurements out that window, you determine that the rocket is accelerating upward at 8.14 m/s². When you drop a ball from a height of 2.15 meters, it hits the floor 0.200 seconds later. What is the value of g for the alien world below you? **Analysis:** Upon dropping the ball from a height of 2.15 meters and observing that it takes 0.200 seconds to hit the floor, we can use the kinematic equations of motion to solve for the gravitational acceleration (g) on the alien planet. We must account for the upward acceleration of the rocket while calculating the net acceleration affecting the ball’s descent. *Given:* - Rocket upward acceleration (a₁) = 8.14 m/s² - Drop height (h) = 2.15 m - Time duration (t) = 0.200 s **Step-by-Step Solution:** 1. Identify the effective downward acceleration (a₂) affecting the ball inside the rocket. \[ a₂ = g + a₁ \] 2. Use the second kinematic equation to relate the height, time, and net acceleration: \[ h = \frac{1}{2} a₂ t² \] Substituting in the known values: \[ 2.15 = \frac{1}{2} a₂ (0.200)² \] Solving for a₂: \[ 2.15 = \frac{1}{2} a₂ (0.04) \] \[ 2.15 = 0.02 a₂ \] \[ a₂ = \frac{2.15}{0.02} = 107.5 m/s² \] 3. Finally, solve for the value of g: \[ g = a₂ - a₁ \] \[ g = 107.5 - 8.14 =
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