OK, this is the last time for one of these crazy adventures. THIS time, though, there is a window in the floor, and you can see that you re in a rocket which has just taken off from the surface of an alien planet. By taking careful measurements out that window you determine that the rocket is accelerating upward at 7.42 m/s^2. When you drop a ball from a height of 1.74 m, it hits the floor 0.254 s later. What is the value of g for the alien world below you? 1. 63.8 m/s^2 2 55.2 m/s^2 3. 79.1 m/s^2 4 46.5 m/s^2

OK, this is the last time for one of these crazy adventures. THIS time, though, there is a window in the floor, and you can see that you re in a rocket which has just taken off from the surface of an alien planet. By taking careful measurements out that window you determine that the rocket is accelerating upward at 7.42 m/s^2. When you drop a ball from a height of 1.74 m, it hits the floor 0.254 s later. What is the value of g for the alien world below you? 1. 63.8 m/s^2 2 55.2 m/s^2 3. 79.1 m/s^2 4 46.5 m/s^2

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Description: OK, this is the last time for one of these crazy adventures. THIS time, though, there is a window in the floor, and you cansee that you re in a rocket which has just taken off from the surface of an alien planet. By taking careful measurementsout th

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Any assistance with this physics problem would be great!
A rocket in free space generates a constant acceleration of (+8x^)[ms2](+8x^)[ms2]. If at t1=4t1=4 [s] the rocket has a velocity of v⃗ 1=−5x^v→1=−5x^ [m/s], what is the rocket's displacement between t1t1 and t2=8t2=8 seconds? Select one: A.−20 [m] B. +256 [m] C. None of these are correct OR there is not enough information D.+472 [m] E.+44 [m] F.+216 [m] G.+59 [m] H.+27 [m] I. +21 [m] J. +108 [m] K.−40 [m] L.+64 [m]
You go watch your friend as she runs at a cross country meet. The first time she passes you, your friend runs by going due north at a speed of 4.40 m/s. You move to a different place on the course and twelve minutes after you saw her the first time, your friend runs past you again. This time she is traveling at a speed of 3.80 m/s in the direction 30.0◦ W of S. What is the direction of her average acceleration between those same two times?
The Hulk, on the 75th story of Stark Tower (225 m off the ground), sees Tony drop his penny. He catches the penny and throws it back to Tony. What is the minimum speed necessary for Hulk's throw in order for the penny to reach Tony? (Note: nobody bothers trying to get Mjolnir back to Thor. He's on his own.)
Please answer this. I will surely upvote!!!
OK, this is the last time for one of these crazy adventures. THIS time, though, there is a window in the floor, and you can see that you re in a rocket which has just taken off from the surface of an alien planet. By taking careful measurements out that window you determine that the rocket is accelerating upward at 9.60 m/s^2. When you drop a ball from a height of 1.20 m, it hits the floor 0.362 s later. What is the value of g for the alien world below you? 16.5 m/s^2 8.7 m/s^2 28.1 m/s^2 18.4 m/s^2
OK, this is the last time for one of these crazy adventures. THIS time, though, there is a window in the floor, and you can see that you re in a rocket which has just taken off from the surface of an alien planet. By taking careful measurements out that window you determine that the rocket is accelerating upward at 7.11 m/s^2. When you drop a ball from a height of 1.08 m, it hits the floor 0.213 s later. What is the value of g for the alien world below you? 49.0 m/s^2 60.8 m/s^2 40.5 m/s^2 57.4 m/s^2
OK, yet another strange awakening in a room with no windows. This time you drop a ball from a height of 1.67 m and it hits the floor 0.292 s after you drop it. This time you suspect you are on a rocket that has just left the surface of the Earth, and is still not too far above the ground. What do you deduce the rocket s acceleration to be? 1 58.8 m/s^2 29.4 m/s^2 3 49.0 m/s^2 4 39.2 m/s^2
A movie stunt woman takes a running jump from the roof of one building to that of a lower building. She leaves the taller building traveling perfectly horizontally at 6.1 m/s and just makes it to the edge of the roof of the lower building. The horizontal gap between the buildings is 2.8 m. The difference in height between the two buildings is 1.0 m O 1.4 m 2.3 m 2.8 m
This time you drop a ball from a height of 1.82 m and it hits the floor 0.365 s after you drop it. This time you suspect you are on a rocket that has just left the surface of the Earth, and is still not too far above the ground. What do you deduce the rocket s acceleration to be? 27.3 m/s^2 33.3 m/s^2 17.5 m/s^2 37.1 m/s^2
How would I begin to solve this problem? In Example 2.6, we considered a simple model for a rocket launched from the surface of the Earth. A better expression for a rocket's position measured from the center of the Earth is given by y(t) = (RE3/2 + 3*(g/2)1/2 REt)2/3 where RE is the radius of the Earth (6.38 ✕ 106 m) and g is the constant acceleration of an object in free fall near the Earth's surface (9.81 m/s2). (a) Derive expressions for vy(t) and ay(t). (Use the following as necessary: g, RE, and t. Do not substitute numerical values; use variables only.)
OK, this is the last time for one of these crazy adventures. THIS time, though, there is a window in the floor, and you can see that you re in a rocket which has just taken off from the surface of an alien planet. By taking careful measurements out that window you determine that the rocket is accelerating upward at 8.00 m/s^2. When you drop a ball from a height of 2.41 m, it hits the floor 0.209 s later. What is the value of g for the alien world below you? a. 111.3 m/s^2 b. 153.5 m/s^2 c. 102.3 m/s^2 d. 120.2 m/s^2