Drew Rosen Automation Company estimates the data entry and verifying times for four jobs as follows:In what order should the jobs be done if the company has one operator for each job?The order isChoose the correct graph of the time-phased flow of this job sequence.O A.O C.Job Entry TimeA2.0Job Verify TimeS2.0- IdleBJob Entry TimeA3.43.4 5.4- IdleAJob Verify TimeAB5.65.4CBB1995.8 7.2 8.2D117.9 9.5D1948.0 9.4 10.5C D1119.4 11.7 13.3Q✔QJOBABCDDATA ENTRY (HOURS)2.03.62.31.6B.O D.VERIFY (HOURS)3.42.41.41.0Job Entry TimeAH2.0Job Verify TimeAㅏJob Entry TimeAH2.0Job Verify TimeD, CH3.41.0 2.4B- IdleBB5.6C5.64C, D5.8 7.2 8.2C7.9B7.98.0DD9.59.5A11.4QGQ

Johnson's rule is a method of assigning jobs to minimize the completion time of a set of jobs in 2 different machines or units (here data entry and verification). The steps for Johnson's rule are:1) Identify the jobs and their completion time across 2 machines. Here is already given.2) across both the activities, consider the activity with the lowest time. If it is on the machine 1 (data entry), schedule this job as first job. If it is on machine 2 (verification) put is last job.3) Once done, repeat the step 2 for 2nd/2nd last, 3rd/3last job and so on.Once an activity is filled, it can is eliminated from further calculation. We'll use the Johnson's rule to find the sequence.As we can see, the lowest time is of activity D in verify. Hence we'll start from left. Therefore, our sequence at the start will be:_ , _ , _ , DNow, the lowest time is of activity C in verify. Hence, we'll fill in second last blank and our sequence proceeds as: _, _, C, DSimilarly, the lowest time is of activity B in verify. Hence, we'll fill up the third last black and and our sequence is:_, B, C, D. Now, activity A will take the first spot.Therefore, the sequence of Activities is A,B,C,D.option b is wrong, because it doesn't consider an idle time. between data entry and verifyOption C is wrong, because data entry starts with an idle time of 3.4 hours and verify starts first, which is wrong.Option D is wrong, because the sequence of activities for data entry and verify is different.Therefore, Option A is correct. Job entry time for Activity A is 2 hours. During that time, verify for activity will be 2 hours of idle time. After 2 hours, it'll run for 3.4 hours. Job entry time for activity B will start immediately after activity A. and will run for 3.6 hours and total as 2 + 3.6 = 5.6. Verification of activity A completes at 5.4, hence there is idle time of 0.2 hours. Once, data entry is finished at 5.6, verify for activity B will start at 5.6 for 2.4 hours, until 8 hours.Job entry time for Activity C will start at 5.6 for up to 2.3 hours, which is 7.9 hours in total. But verification for B finishes at 8, so verification for C will start at 8 only for 1.4 hours, until 9.4 hours.Job entry for activity D will start at 7.9 hours for 1.6 hours, until 9.5. And there will be idle time for 0.1 hours, because verify for activity C completes at 9.4 but entry for D is still in progress. Now, at 9.5 data entry for D starts at 9.5 for 1 hour, until 10.5 hours, which is also the total completion time.A) The correct sequence is: A, B, C, DB) The correct time-phased graph is Option A<--- Answer