Draw three cards randomly from a standard deck of 52 cards and let x be the number of queens in the draw. Evaluate the probabilit p(x) for x = 0, 1, 2, 3 X p(0) = 0.7825 p(1) = 0.2042 p(2) = 0.0130 p(3) = 0.0002

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**Title: Probability of Drawing Queens from a Deck of Cards**

**Problem Statement:**
Draw three cards randomly from a standard deck of 52 cards and let \( x \) be the number of queens in the draw. Evaluate the probability.

**Explanation:**

The problem involves calculating the probability of drawing a certain number of queens when three cards are drawn from a deck. The function \( p(x) \) is defined for values \( x = 0, 1, 2, 3 \). Each \( p(x) \) represents the probability of drawing \( x \) queens.

**Probability Values:**
- \( p(0) = 0.7825 \) 
  - This value is marked incorrect.
- \( p(1) = 0.2042 \) 
  - This value is correct.
- \( p(2) = 0.0130 \) 
  - This value is correct.
- \( p(3) = 0.0002 \) 
  - This value is correct.

**Conclusion:**
The probabilities for drawing 0, 1, 2, and 3 queens are evaluated, with the probability for drawing no queens (\( p(0) \)) initially considered incorrect. The correct calculations would involve using combinations to figure out each scenario's likelihood, ensuring all probabilities sum to 1.
Transcribed Image Text:**Title: Probability of Drawing Queens from a Deck of Cards** **Problem Statement:** Draw three cards randomly from a standard deck of 52 cards and let \( x \) be the number of queens in the draw. Evaluate the probability. **Explanation:** The problem involves calculating the probability of drawing a certain number of queens when three cards are drawn from a deck. The function \( p(x) \) is defined for values \( x = 0, 1, 2, 3 \). Each \( p(x) \) represents the probability of drawing \( x \) queens. **Probability Values:** - \( p(0) = 0.7825 \) - This value is marked incorrect. - \( p(1) = 0.2042 \) - This value is correct. - \( p(2) = 0.0130 \) - This value is correct. - \( p(3) = 0.0002 \) - This value is correct. **Conclusion:** The probabilities for drawing 0, 1, 2, and 3 queens are evaluated, with the probability for drawing no queens (\( p(0) \)) initially considered incorrect. The correct calculations would involve using combinations to figure out each scenario's likelihood, ensuring all probabilities sum to 1.
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