**Educational Resource: Understanding Probabilities in Sobriety Checkpoints****Scenario:** When a man observed a sobriety checkpoint conducted by a police department, he saw 691 drivers were screened and 9 were arrested for driving while intoxicated. Based on those results, we can estimate that $ P(W) = 0.01302 $, where $ W $ denotes the event of screening a driver and getting someone who is intoxicated. What does $ P(W) $ denote, and what is its value?**Question:** What does $ P(W) $ represent?**Options:**- **A.** $ P(W) $ denotes the probability of a driver passing through the sobriety checkpoint.- **B.** $ P(W) $ denotes the probability of screening a driver and finding that he or she is intoxicated.- **C.** $ P(W) $ denotes the probability of screening a driver and finding that he or she is not intoxicated.- **D.** $ P(W) $ denotes the probability of a driver being intoxicated.**Correct Answer:** - **B. $ P(W) $ denotes the probability of screening a driver and finding that he or she is intoxicated.****Calculation:** To compute $ P(W) $, divide the number of drivers found intoxicated (9) by the total number of drivers screened (691): \[ P(W) = \frac{9}{691} \approx 0.01302 \]**Instructions:** Round $ P(W) $ to five decimal places as needed.**Additional Information:** This scenario provides insight into how to calculate the probability of a specific event occurring within a given sample, offering a practical example of statistical analysis and probability theory in real-world situations such as police checkpoints.**Reference:**© 2020 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy | Permissions | Contact Us

When a man observed a sobriety checkpoint conducted by a police department, he saw 691 drivers were screened and 9 were arrested for driving while intoxicated. Based on those results, we can estimate that P(W)30.01302, where W denotes the event of screening a driver and getting someone who is intoxicated. What does P(W) denote, and what is its value? What does P(W) represent? O A. P(W) denotes the probability of a driver passing through the sobriety checkpoint. O B. P(W) denotes the probability of screening a driver and finding that he or she is intoxicated. OC. P(W) denotes the probability of screening a driver and finding that he or she is not intoxicated. O D. P(W) denotes the probability of driver being intoxicated. P(W) =] (Round to five decimal places as needed.) %3D

When a man observed a sobriety checkpoint conducted by a police department, he saw 691 drivers were screened and 9 were arrested for driving while intoxicated. Based on those results, we can estimate that P(W)30.01302, where W denotes the event of screening a driver and getting someone who is intoxicated. What does P(W) denote, and what is its value? What does P(W) represent? O A. P(W) denotes the probability of a driver passing through the sobriety checkpoint. O B. P(W) denotes the probability of screening a driver and finding that he or she is intoxicated. OC. P(W) denotes the probability of screening a driver and finding that he or she is not intoxicated. O D. P(W) denotes the probability of driver being intoxicated. P(W) =] (Round to five decimal places as needed.) %3D

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Recall that Benford's Law claims that numbers chosen from very large data files tend to have "1" as the first nonzero digit disproportionately often. In fact, research has shown that if you randomly draw a number from a very large data file, the probability of getting a number with "1" as the leading digit is about 0.301. Now suppose you are the auditor for a very large corporation. The revenue file contains millions of numbers in a large computer data bank. You draw a random sample of n = 226 numbers from this file and r = 85 have a first nonzero digit of 1. Let p represent the population proportion of all numbers in the computer file that have a leading digit of 1.(i) Test the claim that p is more than 0.301. Use ? = 0.05. (a) What is the level of significance?State the null and alternate hypotheses. H0: p > 0.301; H1: p = 0.301 H0: p = 0.301; H1: p > 0.301 H0: p = 0.301; H1: p < 0.301 H0: p = 0.301; H1: p ≠ 0.301 (b) What sampling distribution will you use? The…
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