Draw the two possible products produced in this E elimination. Ignore any inorganic byproducts. CI

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**Title: Understanding E1 Elimination Reactions**

**Objective:**
To draw the two possible products produced in an E1 elimination reaction, while ignoring any inorganic byproducts.

**Reaction Scheme:**

The initial compound is a chlorinated alkane, which will undergo E1 elimination. The reaction conditions include water (H₂O) and heat, which facilitate the formation of the products.

**Diagram Explanation:**

- **Starting Material:**
  - The diagram shows a structural formula of a chlorinated alkane with a chlorine atom (Cl) attached to a secondary carbon atom. Two identical alkyl groups branch off, and a single alkyl group continues the chain.

- **Reaction Conditions:**
  - The conditions for the reaction are listed as H₂O and heat. These conditions are typical for promoting E1 elimination, where the chlorine acts as a leaving group.

- **Process:**
  - An arrow points downward, indicating the progression of the reaction.

Through these steps, the chlorine atom will leave, resulting in the formation of a carbocation intermediate. This allows for the rearrangement necessary for elimination, producing two possible alkene products—one being the more substituted Zaitsev product, and the other being the less substituted Hoffman product.
Transcribed Image Text:**Title: Understanding E1 Elimination Reactions** **Objective:** To draw the two possible products produced in an E1 elimination reaction, while ignoring any inorganic byproducts. **Reaction Scheme:** The initial compound is a chlorinated alkane, which will undergo E1 elimination. The reaction conditions include water (H₂O) and heat, which facilitate the formation of the products. **Diagram Explanation:** - **Starting Material:** - The diagram shows a structural formula of a chlorinated alkane with a chlorine atom (Cl) attached to a secondary carbon atom. Two identical alkyl groups branch off, and a single alkyl group continues the chain. - **Reaction Conditions:** - The conditions for the reaction are listed as H₂O and heat. These conditions are typical for promoting E1 elimination, where the chlorine acts as a leaving group. - **Process:** - An arrow points downward, indicating the progression of the reaction. Through these steps, the chlorine atom will leave, resulting in the formation of a carbocation intermediate. This allows for the rearrangement necessary for elimination, producing two possible alkene products—one being the more substituted Zaitsev product, and the other being the less substituted Hoffman product.
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