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Draw the timing diagram for V and Z for the circuit. Assume that the AND gate has a delay of 10 ns and the OR gate has a delay of 5 ns. V W X Y V N W- 10 ns 5 as I 1 0 5 10 15 20 25 30 35 40 45 50 551(ns)

Draw the timing diagram for V and Z for the circuit. Assume that the AND gate has a delay of 10 ns and the OR gate has a delay of 5 ns. V W X Y V N W- 10 ns 5 as I 1 0 5 10 15 20 25 30 35 40 45 50 551(ns)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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**Timing Diagram for V and Z in a Circuit with Delay** In this exercise, we draw the timing diagram for the outputs \( V \) and \( Z \) for a given digital circuit. The circuit consists of an AND gate and an OR gate, where the AND gate has a delay of 10 nanoseconds (ns) and the OR gate has a delay of 5 nanoseconds (ns). **Circuit Description:** 1. Inputs \( W \), \( X \), and \( Y \) are fed into the circuit: - \( W \) and \( X \) are inputs to the AND gate. - The output of the AND gate is denoted as \( V \). 2. The output \( V \) is connected to one input of the OR gate, and \( Y \) is connected to the other input of the OR gate. The output of the OR gate is denoted as \( Z \). **Timing Diagram Explanation:** - The horizontal axis represents time in nanoseconds (ns), ranging from 0 to 55 ns. - The vertical lines represent the active high (logic 1) and low (logic 0) states. 1. **Input and Output States:** - \( W \): Logic high from 0 to 10 ns, drops to low from 10 to 20 ns, returns to high from 20 to 30 ns, low again from 30 to 40 ns, and high from 40 to 50 ns. - \( X \): Logic low from 0 to 10 ns, high from 10 to 30 ns, low from 30 to 40 ns, and high from 40 ns onward. - \( Y \): Logic high from 0 to 20 ns, low from 20 to 30 ns, and high from 30 ns onward. 2. **Output \( V \) from the AND Gate:** - Remains low from 0 to 20 ns because both \( W \) and \( X \) need to be high, which isn't the case due to input conditions and gate delay. - Becomes high from 20 to 30 ns as both \( W \) and \( X \) are high. - Goes low from 30 to 40 ns. - Becomes high again from 40 to 50 ns due to the delay after both inputs are high. 3. **
Transcribed Image Text:**Timing Diagram for V and Z in a Circuit with Delay** In this exercise, we draw the timing diagram for the outputs \( V \) and \( Z \) for a given digital circuit. The circuit consists of an AND gate and an OR gate, where the AND gate has a delay of 10 nanoseconds (ns) and the OR gate has a delay of 5 nanoseconds (ns). **Circuit Description:** 1. Inputs \( W \), \( X \), and \( Y \) are fed into the circuit: - \( W \) and \( X \) are inputs to the AND gate. - The output of the AND gate is denoted as \( V \). 2. The output \( V \) is connected to one input of the OR gate, and \( Y \) is connected to the other input of the OR gate. The output of the OR gate is denoted as \( Z \). **Timing Diagram Explanation:** - The horizontal axis represents time in nanoseconds (ns), ranging from 0 to 55 ns. - The vertical lines represent the active high (logic 1) and low (logic 0) states. 1. **Input and Output States:** - \( W \): Logic high from 0 to 10 ns, drops to low from 10 to 20 ns, returns to high from 20 to 30 ns, low again from 30 to 40 ns, and high from 40 to 50 ns. - \( X \): Logic low from 0 to 10 ns, high from 10 to 30 ns, low from 30 to 40 ns, and high from 40 ns onward. - \( Y \): Logic high from 0 to 20 ns, low from 20 to 30 ns, and high from 30 ns onward. 2. **Output \( V \) from the AND Gate:** - Remains low from 0 to 20 ns because both \( W \) and \( X \) need to be high, which isn't the case due to input conditions and gate delay. - Becomes high from 20 to 30 ns as both \( W \) and \( X \) are high. - Goes low from 30 to 40 ns. - Becomes high again from 40 to 50 ns due to the delay after both inputs are high. 3. **
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