Draw the structure of ß-D-Glucose
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
Related questions
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![### Task: Drawing the Structure of β-D-Glucose
**Instruction:**
"Draw the structure of β-D-Glucose"
#### Explanation:
β-D-Glucose is a common form of glucose, an important sugar in biology. Glucose is a hexose (six-carbon) sugar and is the most important carbohydrate in biology. β-D-Glucose, specifically, has a particular ring structure where the OH group on the anomeric carbon (carbon-1) is on the opposite side of the CH2OH group.
For clarity and further understanding:
1. Start by drawing a six-membered ring (pyranose form), which resembles a hexagon.
2. Number the carbon atoms in the ring from 1 through 6, starting from the oxygen atom and moving clockwise.
3. Add the hydroxyl groups:
- Carbon 1 (C1): OH (beta position, which means it is above the plane of the ring)
- Carbon 2 (C2): OH (to the right)
- Carbon 3 (C3): OH (to the left)
- Carbon 4 (C4): OH (to the right)
- Carbon 5 (C5): OH is part of the ring, CH2OH above the ring
4. The remaining hydrogen atoms fill the other gaps.
Use this guidance to manually draw the structure of β-D-Glucose. If possible, refer to a chemist's rendering of this molecule to ensure precision.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc62819af-1f81-4d59-bfb3-1ca1702855ed%2Facfb11ba-2d4d-4f64-9b3c-f877ae6f7c91%2Fkqa5y7k_processed.png&w=3840&q=75)
Transcribed Image Text:### Task: Drawing the Structure of β-D-Glucose
**Instruction:**
"Draw the structure of β-D-Glucose"
#### Explanation:
β-D-Glucose is a common form of glucose, an important sugar in biology. Glucose is a hexose (six-carbon) sugar and is the most important carbohydrate in biology. β-D-Glucose, specifically, has a particular ring structure where the OH group on the anomeric carbon (carbon-1) is on the opposite side of the CH2OH group.
For clarity and further understanding:
1. Start by drawing a six-membered ring (pyranose form), which resembles a hexagon.
2. Number the carbon atoms in the ring from 1 through 6, starting from the oxygen atom and moving clockwise.
3. Add the hydroxyl groups:
- Carbon 1 (C1): OH (beta position, which means it is above the plane of the ring)
- Carbon 2 (C2): OH (to the right)
- Carbon 3 (C3): OH (to the left)
- Carbon 4 (C4): OH (to the right)
- Carbon 5 (C5): OH is part of the ring, CH2OH above the ring
4. The remaining hydrogen atoms fill the other gaps.
Use this guidance to manually draw the structure of β-D-Glucose. If possible, refer to a chemist's rendering of this molecule to ensure precision.
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