Draw the reaction product for the following SN2 reaction b.) What is the best description of the product(s) that form? single enantiomer, achiral product, pair of enantiomers or pair of diastereomers
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
a.) Draw the reaction product for the following SN2 reaction
b.) What is the best description of the product(s) that form?
single enantiomer, achiral product, pair of enantiomers or pair of diastereomers
![**Transcription for Educational Website:**
**Title: Understanding the Product of an S<sub>N</sub>2 Reaction**
**Introduction:**
In organic chemistry, S<sub>N</sub>2 reactions are a type of nucleophilic substitution where a nucleophile attacks an electrophilic carbon, leading to the displacement of a leaving group. The S<sub>N</sub>2 mechanism is characterized by a single, concerted step where bond-making and bond-breaking occur simultaneously, which often inverts the configuration at the carbon center.
**Task:**
Draw the reaction product for the following S<sub>N</sub>2 reaction:
**Reaction Details:**
- **Reactant Structure:** The reactant is a chlorinated alkane with a chiral center, indicated by the wedged and dashed bonds for the chlorine atom, signifying its three-dimensional orientation. The structure consists of an ethyl group (two carbon atoms), with chlorine (Cl) attached to the second carbon in a wedge orientation (indicating it is coming out of the plane towards the viewer).
- **Reagent:** Sodium cyanide (NaCN) is shown reacting with the chlorinated compound.
- **Arrow Indication:** A single-headed arrow points from the reactants to where the product is expected, indicating the direction of the chemical transformation.
**Expected Product:**
In this S<sub>N</sub>2 reaction, the cyanide ion (CN<sup>-</sup>) from NaCN will act as the nucleophile. It will attack the electrophilic carbon, where the chlorine atom is currently attached, leading to the displacement of the chloride ion (Cl<sup>-</sup>). As a result of this backside attack, the configuration at the carbon center will invert, leading to the formation of an alkyl cyanide with the CN group taking the place of the chlorine atom.
By understanding these reaction mechanisms and anticipating the resulting product, we can better predict and manipulate chemical reactions in synthetic organic chemistry.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F89b818ed-2b56-4ed1-ae0c-ef21eaac3b75%2F68c8d9c0-f722-4ce2-a9d5-76915333ef03%2Fz2bica8_processed.png&w=3840&q=75)
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