Draw the product of this reaction. Ignore inorganic byproducts. Br2 (2 equiv) Br or Br Select to Edit

World of Chemistry, 3rd edition
3rd Edition
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter20: Organic Chemistry
Section20.3: Introduction To Functional Groups And Alcohols
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**Title: Reaction of Alkynes with Bromine**

**Reaction Overview:**

This exercise asks to draw the product of the reaction between a phenylacetylene and two equivalents of bromine (Br₂), while ignoring inorganic byproducts.

**Reactants:**

- **Phenylacetylene**: A compound with a benzene ring attached to an alkyne group (C≡CH).

**Reagent:**

- **Br₂ (2 equiv)**: Two equivalents of bromine are used to react with the alkyne.

**Reaction Mechanism:**

1. The alkyne undergoes a halogenation reaction with bromine.
2. The triple bond reacts with two equivalents of Br₂, adding a bromine atom to each carbon of the former triple bond, resulting in a tetrahalo compound.

**Product:**

- The result is a dibromoalkene with a benzene ring, having both bromine atoms added across the former alkyne bond.

**Diagram Explanation:**

- **Top Structure**: Shows the reactant, phenylacetylene.
- **Arrow**: Indicates the direction of the reaction, leading from the reactant to the product.
- **Br₂ (2 equiv)**: Notation for the reagent used in the reaction.
- **Bottom Structure**: Displays the product structure with bromine atoms added to the carbons of the former alkyne bond.

This reaction is a typical example of how alkynes can be fully saturated by halogenation.
Transcribed Image Text:**Title: Reaction of Alkynes with Bromine** **Reaction Overview:** This exercise asks to draw the product of the reaction between a phenylacetylene and two equivalents of bromine (Br₂), while ignoring inorganic byproducts. **Reactants:** - **Phenylacetylene**: A compound with a benzene ring attached to an alkyne group (C≡CH). **Reagent:** - **Br₂ (2 equiv)**: Two equivalents of bromine are used to react with the alkyne. **Reaction Mechanism:** 1. The alkyne undergoes a halogenation reaction with bromine. 2. The triple bond reacts with two equivalents of Br₂, adding a bromine atom to each carbon of the former triple bond, resulting in a tetrahalo compound. **Product:** - The result is a dibromoalkene with a benzene ring, having both bromine atoms added across the former alkyne bond. **Diagram Explanation:** - **Top Structure**: Shows the reactant, phenylacetylene. - **Arrow**: Indicates the direction of the reaction, leading from the reactant to the product. - **Br₂ (2 equiv)**: Notation for the reagent used in the reaction. - **Bottom Structure**: Displays the product structure with bromine atoms added to the carbons of the former alkyne bond. This reaction is a typical example of how alkynes can be fully saturated by halogenation.
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