Draw the major product of this reaction. Ignore inorganic byproducts. Cl2 H₂O

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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The image presents a chemical reaction where a cyclopentene molecule reacts with chlorine (Cl₂) and water (H₂O). The task is to draw the major product of this reaction while ignoring any inorganic byproducts.

**Description of Reaction:**

1. **Starting Material:**
   - A cyclopentene ring is depicted with a double bond, indicating unsaturation.

2. **Reagents:**
   - Chlorine (Cl₂)
   - Water (H₂O)

**Expected Major Product:**

In the presence of Cl₂ and H₂O, the reaction typically results in a halohydrin formation. The expected mechanism involves:
- The addition of Cl₂ across the double bond in a syn manner.
- Water acts as a nucleophile and is added to the more substituted carbon atom due to Markovnikov’s rule.

This generally results in the formation of a chlorohydrin where:
- A chlorine atom and a hydroxyl group (OH) are added across the former double bond of the cyclopentene.

The major product would therefore be 1-chloro-2-hydroxycyclopentane. The chlorine and hydroxyl groups will be on adjacent carbon atoms that were previously part of the double bond.
Transcribed Image Text:The image presents a chemical reaction where a cyclopentene molecule reacts with chlorine (Cl₂) and water (H₂O). The task is to draw the major product of this reaction while ignoring any inorganic byproducts. **Description of Reaction:** 1. **Starting Material:** - A cyclopentene ring is depicted with a double bond, indicating unsaturation. 2. **Reagents:** - Chlorine (Cl₂) - Water (H₂O) **Expected Major Product:** In the presence of Cl₂ and H₂O, the reaction typically results in a halohydrin formation. The expected mechanism involves: - The addition of Cl₂ across the double bond in a syn manner. - Water acts as a nucleophile and is added to the more substituted carbon atom due to Markovnikov’s rule. This generally results in the formation of a chlorohydrin where: - A chlorine atom and a hydroxyl group (OH) are added across the former double bond of the cyclopentene. The major product would therefore be 1-chloro-2-hydroxycyclopentane. The chlorine and hydroxyl groups will be on adjacent carbon atoms that were previously part of the double bond.
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