Draw the product of this reaction. Ignore inorganic byproducts. Br Br КОН, Д Drawing

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Transcription and Explanation:**

**Instruction:**
"Draw the product of this reaction. Ignore inorganic byproducts."

**Chemical Reaction:**
- The starting compound is a dibromo alkane, specifically a 2,3-dibromopentane.
- The reaction condition indicated is the presence of potassium hydroxide (KOH) and heat (denoted by the delta symbol, Δ).

**Reaction Description:**
- The major reaction mechanism likely involves an elimination process. The KOH in heat promotes the elimination of two molecules of HBr from the dibromo compound.
- This elimination typically results in the formation of a conjugated diene, where two double bonds form in the carbon chain due to the removal of the bromine atoms and the corresponding hydrogen atoms.

**Diagram Explanation:**
There is an empty dotted red box labeled "Drawing" where the product structure needs to be drawn.

**Expected Product:**
- The expected product after this reaction is 1,3-pentadiene. This is a conjugated diene resulting from the elimination of HBr molecules across the 2,3-dibromo positions of the alkane.

**Conclusion:**
- Students or individuals learning from this educational content would use this setup to practice predicting products of elimination reactions using strong bases and heat.
Transcribed Image Text:**Transcription and Explanation:** **Instruction:** "Draw the product of this reaction. Ignore inorganic byproducts." **Chemical Reaction:** - The starting compound is a dibromo alkane, specifically a 2,3-dibromopentane. - The reaction condition indicated is the presence of potassium hydroxide (KOH) and heat (denoted by the delta symbol, Δ). **Reaction Description:** - The major reaction mechanism likely involves an elimination process. The KOH in heat promotes the elimination of two molecules of HBr from the dibromo compound. - This elimination typically results in the formation of a conjugated diene, where two double bonds form in the carbon chain due to the removal of the bromine atoms and the corresponding hydrogen atoms. **Diagram Explanation:** There is an empty dotted red box labeled "Drawing" where the product structure needs to be drawn. **Expected Product:** - The expected product after this reaction is 1,3-pentadiene. This is a conjugated diene resulting from the elimination of HBr molecules across the 2,3-dibromo positions of the alkane. **Conclusion:** - Students or individuals learning from this educational content would use this setup to practice predicting products of elimination reactions using strong bases and heat.
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