Draw the product of the E2 reaction shown below. Ignore any inorganic byproducts. CI

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Question 9 of 21**

**Task:**
Draw the product of the E2 reaction shown below. Ignore any inorganic byproducts.

**Reactants:**
The diagram shows a 2-chlorobutane molecule with a chlorine (Cl) atom attached to the second carbon of a four-carbon chain. 

**Reagent:**
NaOH (sodium hydroxide) is used as the reagent for the E2 reaction.

**Instructions:**
Please select a drawing or reagent from the question area on the right to illustrate the product of the reaction.

**Explanation:**
In an E2 elimination reaction, a strong base like NaOH abstracts a beta hydrogen (a hydrogen atom on the carbon adjacent to the one bearing the leaving group) leading to the formation of a double bond. This results in an alkene as the product. In this specific reaction's setup, the chlorine atom acts as the leaving group.
Transcribed Image Text:**Question 9 of 21** **Task:** Draw the product of the E2 reaction shown below. Ignore any inorganic byproducts. **Reactants:** The diagram shows a 2-chlorobutane molecule with a chlorine (Cl) atom attached to the second carbon of a four-carbon chain. **Reagent:** NaOH (sodium hydroxide) is used as the reagent for the E2 reaction. **Instructions:** Please select a drawing or reagent from the question area on the right to illustrate the product of the reaction. **Explanation:** In an E2 elimination reaction, a strong base like NaOH abstracts a beta hydrogen (a hydrogen atom on the carbon adjacent to the one bearing the leaving group) leading to the formation of a double bond. This results in an alkene as the product. In this specific reaction's setup, the chlorine atom acts as the leaving group.
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