Draw the product formed by the reaction of t-butoxide with (1R,2S)-1-bromo-2-methyl-1-phenylbutane. Draw the correct stereoisomer of the product. Select Draw Rings More Erase H H H Br (CH3);CO-K* (CH3)3COH Ill

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**Title: Reaction of t-butoxide with (1R,2S)-1-bromo-2-methyl-1-phenylbutane**

**Objective:**
To determine and draw the correct stereoisomer of the product formed in the reaction of t-butoxide with (1R,2S)-1-bromo-2-methyl-1-phenylbutane.

**Reaction Overview:**
- **Reactants:** 
  - (1R,2S)-1-bromo-2-methyl-1-phenylbutane
  - Potassium t-butoxide, (CH₃)₃CO⁻K⁺
  - Solvent: tert-butanol, (CH₃)₃COH

**Chemical Structure of the Reactant:**
- The structure exhibits a chiral carbon attached to a bromine atom, a hydrogen atom, a methyl group, and a phenyl ring. 
- Fisher projection indicates the stereochemistry as (1R,2S).

**Reaction Mechanism:**
- **Elimination Reaction (E2):** The reaction proceeds via an E2 mechanism with the abstraction of a proton by the base (t-butoxide) from the beta-carbon, resulting in the elimination of the bromide ion and the formation of an alkene.

**Graph/Diagram Explanation:**
- The diagram shows the molecular structure of (1R,2S)-1-bromo-2-methyl-1-phenylbutane on the left.
- The reaction arrow points towards the right, indicating the transformation into the product.
- The drawing interface provided on the right is used to sketch the resultant stereoisomer product by selecting and arranging elements like carbon (C), hydrogen (H), and oxygen (O).

**Expected Output:**
- The resulting product should be sketched as an alkene, considering the correct stereochemistry and elimination of the leaving group.

**Tools for Drawing:**
- The interface allows the use of lines to represent bonds and includes options for selecting specific molecular components (C, H, O).
- Tools to rotate and undo are provided to assist in accurate depiction of the molecular structure.

**Conclusion:**
Following the reaction conditions and mechanism, the correct stereoisomer of the product should be drawn to reflect the changes resulting from the reaction of t-butoxide with the given chiral alkyl halide.
Transcribed Image Text:**Title: Reaction of t-butoxide with (1R,2S)-1-bromo-2-methyl-1-phenylbutane** **Objective:** To determine and draw the correct stereoisomer of the product formed in the reaction of t-butoxide with (1R,2S)-1-bromo-2-methyl-1-phenylbutane. **Reaction Overview:** - **Reactants:** - (1R,2S)-1-bromo-2-methyl-1-phenylbutane - Potassium t-butoxide, (CH₃)₃CO⁻K⁺ - Solvent: tert-butanol, (CH₃)₃COH **Chemical Structure of the Reactant:** - The structure exhibits a chiral carbon attached to a bromine atom, a hydrogen atom, a methyl group, and a phenyl ring. - Fisher projection indicates the stereochemistry as (1R,2S). **Reaction Mechanism:** - **Elimination Reaction (E2):** The reaction proceeds via an E2 mechanism with the abstraction of a proton by the base (t-butoxide) from the beta-carbon, resulting in the elimination of the bromide ion and the formation of an alkene. **Graph/Diagram Explanation:** - The diagram shows the molecular structure of (1R,2S)-1-bromo-2-methyl-1-phenylbutane on the left. - The reaction arrow points towards the right, indicating the transformation into the product. - The drawing interface provided on the right is used to sketch the resultant stereoisomer product by selecting and arranging elements like carbon (C), hydrogen (H), and oxygen (O). **Expected Output:** - The resulting product should be sketched as an alkene, considering the correct stereochemistry and elimination of the leaving group. **Tools for Drawing:** - The interface allows the use of lines to represent bonds and includes options for selecting specific molecular components (C, H, O). - Tools to rotate and undo are provided to assist in accurate depiction of the molecular structure. **Conclusion:** Following the reaction conditions and mechanism, the correct stereoisomer of the product should be drawn to reflect the changes resulting from the reaction of t-butoxide with the given chiral alkyl halide.
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