B. What type of elimination reaction is this: E1 or E2? Explain. C. Explain how the leveling effect has occurred in this reaction? D. What is the likely base in the last step: water or HSOA ? Explain.

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**B. What type of elimination reaction is this: E1 or E2? Explain.**

**C. Explain how the leveling effect has occurred in this reaction.**

**D. What is the likely base in the last step: water or HSO₄⁻? Explain.**
Transcribed Image Text:**B. What type of elimination reaction is this: E1 or E2? Explain.** **C. Explain how the leveling effect has occurred in this reaction.** **D. What is the likely base in the last step: water or HSO₄⁻? Explain.**
**Mechanism:**

**Step II**

This diagram illustrates the mechanism of converting cyclohexanol to cyclohexene through a series of protonation and elimination reactions.

1. **Initial Reactants:**
   - Cyclohexanol (\[\mathrm{C_6H_{11}OH}\]) reacts with sulfuric acid (\[H_2SO_4\]).

2. **Protonation of Alcohol by Acid:**
   - The hydroxyl group (\[OH\]) on cyclohexanol is protonated by sulfuric acid, forming a hydronium ion.

3. **Formation of Oxonium Ion:**
   - This protonation results in the formation of an oxonium ion, making the hydroxide a better leaving group.

4. **Loss of the Leaving Group:**
   - Water (\[H_2O\]) is eliminated, leaving behind a carbocation intermediate.

5. **Formation of Cyclohexene:**
   - The proton is abstracted by the conjugate base (\[HSO_4^-\]), leading to the formation of a double bond and resulting in cyclohexene (\[\mathrm{C_6H_{10}}\]).

This series of reactions highlights the conversion of an alcohol to an alkene through acid-catalyzed dehydration.
Transcribed Image Text:**Mechanism:** **Step II** This diagram illustrates the mechanism of converting cyclohexanol to cyclohexene through a series of protonation and elimination reactions. 1. **Initial Reactants:** - Cyclohexanol (\[\mathrm{C_6H_{11}OH}\]) reacts with sulfuric acid (\[H_2SO_4\]). 2. **Protonation of Alcohol by Acid:** - The hydroxyl group (\[OH\]) on cyclohexanol is protonated by sulfuric acid, forming a hydronium ion. 3. **Formation of Oxonium Ion:** - This protonation results in the formation of an oxonium ion, making the hydroxide a better leaving group. 4. **Loss of the Leaving Group:** - Water (\[H_2O\]) is eliminated, leaving behind a carbocation intermediate. 5. **Formation of Cyclohexene:** - The proton is abstracted by the conjugate base (\[HSO_4^-\]), leading to the formation of a double bond and resulting in cyclohexene (\[\mathrm{C_6H_{10}}\]). This series of reactions highlights the conversion of an alcohol to an alkene through acid-catalyzed dehydration.
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