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Draw the Newman projection so that it corresponds to the molecule and conformation shown when viewed down the red bond in the direction of the red arrow. Your projection should be oriented as shown by the arrow marked up. So the CH₂CH3 group on the front carbon should be above the OH and H₂C groups, no matter which template you use. 136 Hom HO up Br Select a template to begin. X G

Draw the Newman projection so that it corresponds to the molecule and conformation shown when viewed down the red bond in the direction of the red arrow. Your projection should be oriented as shown by the arrow marked up. So the CH₂CH3 group on the front carbon should be above the OH and H₂C groups, no matter which template you use. 136 Hom HO up Br Select a template to begin. X G

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Draw the Newman projection so that it corresponds to the molecule and conformation shown when viewed down the red bond in the direction of the red arrow. Your projection should be oriented as shown by the arrow marked up. So the CH₂CH3 group on the front carbon should be above the OH and H₂C groups, no matter which template you use. IX HO up Ø & Br Select a template to begin. X Ś
Transcribed Image Text:Draw the Newman projection so that it corresponds to the molecule and conformation shown when viewed down the red bond in the direction of the red arrow. Your projection should be oriented as shown by the arrow marked up. So the CH₂CH3 group on the front carbon should be above the OH and H₂C groups, no matter which template you use. IX HO up Ø & Br Select a template to begin. X Ś
Expert Solution
Step 1: Introduction

Aligning the front carbon of the Newman projection with one of the sawhorse projection's carbon atoms and then drawing the groups around both carbons is the process of converting a sawhorse projection to a Newman projection. In the Newman projection, the dihedral angle is equivalent to the angle between the groups in the sawhorse projection. This conversion makes it easier to see a molecule's three-dimensional structure along a particular bond.


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