Draw the most stable form of the major mixed Claisen product formed in the reaction. Select Draw Rings 1. NaOC2H5 2. H3O* C2H5OH +

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**Title: Understanding Mixed Claisen Ester Condensation**

**Objective:** 
Learn how to draw the most stable form of the major mixed Claisen product formed in the given reaction.

**Reaction Overview:**

- **Reactants:** 
  - Two esters, a propionate ester and an ethyl acetate.
  
- **Reagents:**
  1. Sodium ethoxide (NaOC₂H₅)
  2. Acidic workup (H₃O⁺)

- **Solvent:** Ethanol (C₂H₅OH)

**Mechanism Explanation:**

1. **Deprotonation:** 
   Sodium ethoxide (NaOC₂H₅) deprotonates the alpha-hydrogen of one of the esters, forming an enolate ion.

2. **Nucleophilic Attack:**
   The enolate ion attacks the carbonyl carbon of the other ester, leading to the formation of a β-keto ester intermediate.

3. **Protonation:**
   Acidic workup (H₃O⁺) protonates the alkoxide intermediate, resulting in the stable Claisen condensation product.

**Structural Insight:**

- Both ester groups participate in the reaction, but the more substituted enolate is typically favored in mixed Claisen reactions.
- The major product is a β-keto ester.

**Key Learning Points:**

- Recognize how mixed Claisen condensations form key carbon-carbon bonds.
- Understand the role of each reagent and solvent in the mechanism.
- Predict the structure of the Claisen product by considering enolate formation and nucleophilic acyl substitution.

This reaction is integral in organic synthesis, providing a pathway to create complex molecules from simple ester precursors. Understanding this process aids in mastering broader synthetic strategies in chemistry.
Transcribed Image Text:**Title: Understanding Mixed Claisen Ester Condensation** **Objective:** Learn how to draw the most stable form of the major mixed Claisen product formed in the given reaction. **Reaction Overview:** - **Reactants:** - Two esters, a propionate ester and an ethyl acetate. - **Reagents:** 1. Sodium ethoxide (NaOC₂H₅) 2. Acidic workup (H₃O⁺) - **Solvent:** Ethanol (C₂H₅OH) **Mechanism Explanation:** 1. **Deprotonation:** Sodium ethoxide (NaOC₂H₅) deprotonates the alpha-hydrogen of one of the esters, forming an enolate ion. 2. **Nucleophilic Attack:** The enolate ion attacks the carbonyl carbon of the other ester, leading to the formation of a β-keto ester intermediate. 3. **Protonation:** Acidic workup (H₃O⁺) protonates the alkoxide intermediate, resulting in the stable Claisen condensation product. **Structural Insight:** - Both ester groups participate in the reaction, but the more substituted enolate is typically favored in mixed Claisen reactions. - The major product is a β-keto ester. **Key Learning Points:** - Recognize how mixed Claisen condensations form key carbon-carbon bonds. - Understand the role of each reagent and solvent in the mechanism. - Predict the structure of the Claisen product by considering enolate formation and nucleophilic acyl substitution. This reaction is integral in organic synthesis, providing a pathway to create complex molecules from simple ester precursors. Understanding this process aids in mastering broader synthetic strategies in chemistry.
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