Draw the major organic product for the reaction shown. The image depicts a chemical reaction involving a ketone and a two-step reduction process.### Structure:- **Reactant:** The organic molecule shown is a ketone with the structure of 3-methylbutanal. The molecule has the following details: - A methyl group (CH₃) attached to the second carbon. - An aldehyde group (C=O with a hydrogen atom) at the end of the chain.### Reaction Steps:1. **NaBH₄ (Sodium Borohydride):** This step introduces sodium borohydride, a reducing agent commonly used to reduce aldehydes and ketones to alcohols.2. **H₂O (Water):** The addition of water follows the sodium borohydride reduction, typically to assist in the reaction completion and workup.### Explanation:In this reaction, 3-methylbutanal undergoes reduction, where the aldehyde group is transformed into a primary alcohol. Sodium borohydride serves as the reducing agent, providing the necessary hydride ions, and the reaction is finalized with water to yield the alcohol product. This process exemplifies a common method in organic chemistry to convert carbonyl compounds into alcohols.

The given reactant molecule is 3,3-dimethyl butanal. The reduction of an aldehyde with sodium borohydride followed by hydrolysis gives primary alcohol. The reduction of ketones with the same reagent gives secondary alcohol.The given substrate is an aldehyde and the reduction of 3,3-dimethyl butanal gives 3,3-dimethyl-butan-1-ol. The reaction is as follows: