Draw the major monobromination product when the alkane shown is subjected to radical bromination at 25 °C. Br2 Br light

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Draw the major monobromination product when the alkane shown is subjected to radical bromination at 25 °C.

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**Title: Radical Bromination of Alkanes**

**Introduction:**

In this exercise, we explore the radical bromination of alkanes to identify the major monobromination product. Bromination is a selective reaction that often places a bromine atom at the most substituted carbon of a hydrocarbon chain due to the stability of the resultant radical.

**Problem Statement:**

Draw the major monobromination product when the alkane shown is subjected to radical bromination at 25 °C.

**Reaction Details:**

- **Reactants:** An alkane, specifically 2-methylbutane, is subjected to bromination.
- **Reagent:** Br\(_2\) under the influence of light.
  
**Mechanism:**

1. **Initiation:** Light splits the Br\(_2\) molecule into two bromine radicals.
2. **Propagation:**
   - A bromine radical abstracts a hydrogen atom from the alkane, forming HBr and a carbon radical.
   - The carbon radical reacts with another Br\(_2\) molecule to form the brominated alkane and another bromine radical.
3. **Termination:** Radicals combine to end the chain reaction.

**Diagram Explanation:**

- **Reactant Structure:** The left structure shows 2-methylbutane.
- **Product Structure:** The right structure is 2-bromo-2-methylbutane. Here, the bromine atom is added to the tert-butyl carbon, as radical stability directs the reaction to the most substituted carbon.

**Conclusion:**

Radical bromination primarily forms the major product by adding bromine to the more stable, more substituted carbon. In this example, the product is 2-bromo-2-methylbutane, demonstrating the chemoselectivity of the radical bromination process.
Transcribed Image Text:**Title: Radical Bromination of Alkanes** **Introduction:** In this exercise, we explore the radical bromination of alkanes to identify the major monobromination product. Bromination is a selective reaction that often places a bromine atom at the most substituted carbon of a hydrocarbon chain due to the stability of the resultant radical. **Problem Statement:** Draw the major monobromination product when the alkane shown is subjected to radical bromination at 25 °C. **Reaction Details:** - **Reactants:** An alkane, specifically 2-methylbutane, is subjected to bromination. - **Reagent:** Br\(_2\) under the influence of light. **Mechanism:** 1. **Initiation:** Light splits the Br\(_2\) molecule into two bromine radicals. 2. **Propagation:** - A bromine radical abstracts a hydrogen atom from the alkane, forming HBr and a carbon radical. - The carbon radical reacts with another Br\(_2\) molecule to form the brominated alkane and another bromine radical. 3. **Termination:** Radicals combine to end the chain reaction. **Diagram Explanation:** - **Reactant Structure:** The left structure shows 2-methylbutane. - **Product Structure:** The right structure is 2-bromo-2-methylbutane. Here, the bromine atom is added to the tert-butyl carbon, as radical stability directs the reaction to the most substituted carbon. **Conclusion:** Radical bromination primarily forms the major product by adding bromine to the more stable, more substituted carbon. In this example, the product is 2-bromo-2-methylbutane, demonstrating the chemoselectivity of the radical bromination process.
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