Draw the Line Bond Structure for oxygen difluoride (OF₂) Step 1: Count the total number of valence electrons from all the atoms in the molecule. Step 2: Draw the "Skeleton Structure" -Attach the atoms together with single bonds in the most symmetric way possible. Central atom is: Chemical formula of molecule Atom # of atoms X X X # of valence electrons = = = Total # of electrons in structure = totals Step 3: Subtract the number of electrons used to make the skeleton structure from the total number of valence electrons. Total # of electrons in structure (from step 1 above) # of electrons used in skeleton (from step 2 above) Remaining # electrons to be added= Step 5: Check for Octets Check the structure in step 4 for octets (4 pairs) of electrons around each atom. If octet rule is satisfied, you are done. If octet rule is not satisfied, go to Step 6. Draw skeleton: # of electrons used in skeleton = (multiply # of bonds in skeleton by 2) Step 4: Add the remaining electrons as lone pairs as evenly as possible on all atoms except hydrogen. First: Re-draw skeleton here: Add remaining electrons to the skeleton as lone pairs Step 6: Use existing lone pairs to make double or triple bonds until the octet rule is satisfied for all atoms

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Draw the Line Bond Structure for oxygen difluoride (OF₂)
Step 1: Count the total number of
valence electrons from all the atoms in
the molecule.
Step 2: Draw the "Skeleton Structure"
-Attach the atoms together with single
bonds in the most symmetric way possible.
Central atom is:
Chemical formula of molecule
Atom # of
atoms
X
X
X
# of
valence
electrons
=
Total # of electrons in structure=
totals
Step 3: Subtract the number of
electrons used to make the skeleton
structure from the total number of
valence electrons.
Total # of electrons in structure
(from step 1 above)
# of electrons used in skeleton
(from step 2 above)
Remaining # electrons to be added=
Step 5: Check for Octets
Check the structure in step 4 for octets
(4 pairs) of electrons around each atom.
If octet rule is satisfied, you are done.
If octet rule is not satisfied, go to Step 6.
Draw skeleton:
# of electrons used in skeleton =
(multiply # of bonds in skeleton by 2)
Step 4: Add the remaining electrons as
lone pairs as evenly as possible on all
atoms except hydrogen.
First: Re-draw skeleton here:
Add remaining electrons to the skeleton as
lone pairs
Step 6: Use existing lone pairs to make
double or triple bonds until the octet rule is
satisfied for all atoms
Transcribed Image Text:Draw the Line Bond Structure for oxygen difluoride (OF₂) Step 1: Count the total number of valence electrons from all the atoms in the molecule. Step 2: Draw the "Skeleton Structure" -Attach the atoms together with single bonds in the most symmetric way possible. Central atom is: Chemical formula of molecule Atom # of atoms X X X # of valence electrons = Total # of electrons in structure= totals Step 3: Subtract the number of electrons used to make the skeleton structure from the total number of valence electrons. Total # of electrons in structure (from step 1 above) # of electrons used in skeleton (from step 2 above) Remaining # electrons to be added= Step 5: Check for Octets Check the structure in step 4 for octets (4 pairs) of electrons around each atom. If octet rule is satisfied, you are done. If octet rule is not satisfied, go to Step 6. Draw skeleton: # of electrons used in skeleton = (multiply # of bonds in skeleton by 2) Step 4: Add the remaining electrons as lone pairs as evenly as possible on all atoms except hydrogen. First: Re-draw skeleton here: Add remaining electrons to the skeleton as lone pairs Step 6: Use existing lone pairs to make double or triple bonds until the octet rule is satisfied for all atoms
Expert Solution
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The octet rule : It refers to the tendency of atoms to prefer to have eight electrons in the valence shell.

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