**Title: Analyzing Velocity Versus Time Graphs**This image provides a velocity-versus-time graph from which an acceleration-versus-time graph is requested to be drawn. The graph plots velocity ($v$) on the vertical axis against time ($t$) on the horizontal axis. **Graph Description:**1. **Velocity Change:** - The graph starts at a velocity of 2 m/s at time $t=0$. - The velocity decreases linearly to -16 m/s at $t=8$ seconds, indicating constant negative acceleration. - From $t=8$ seconds to $t=26$ seconds, the velocity remains constant at -16 m/s, indicating no acceleration. - From $t=26$ seconds to $t=36$ seconds, the velocity decreases linearly from -16 m/s to -22 m/s, indicating another period of constant negative acceleration.2. **Key Graph Sections:** - **0 to 8 seconds:** Linear decrease in velocity indicates constant negative acceleration. Its slope can be calculated by the change in velocity divided by the change in time: $(-16 - 2) / (8 - 0) = -18/8 = -2.25$ m/s². - **8 to 26 seconds:** Constant velocity implies zero acceleration. - **26 to 36 seconds:** Linear decrease in velocity from -16 m/s to -22 m/s implies another constant negative acceleration with a slope of: $(-22 - (-16)) / (36 - 26) = -6/10 = -0.6$ m/s².**Conclusion:**To draw the acceleration-versus-time graph:- Plot a horizontal line at -2.25 m/s² from 0 to 8 seconds.- A zero acceleration line from 8 to 26 seconds.- A horizontal line at -0.6 m/s² from 26 to 36 seconds.This representation will visually depict how acceleration changes over time at different intervals based on the given velocity data.

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Description: **Title: Analyzing Velocity Versus Time Graphs**This image provides a velocity-versus-time graph from which an acceleration-versus-time graph is requested to be drawn. The graph plots velocity ($v$) on the vertical axis against time ($t$) on the

The graph shows the velocity curve Since, acceleration = (Change in Velocity ) / ( Change in time )…

Answered: Draw an acceleration-versus-time graph…

Math

Calculus

Draw an acceleration-versus-time graph corresponding to the below velocity-versus-time graph

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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**Title: Analyzing Velocity Versus Time Graphs**

This image provides a velocity-versus-time graph from which an acceleration-versus-time graph is requested to be drawn. The graph plots velocity ($v$) on the vertical axis against time ($t$) on the horizontal axis.

**Graph Description:**

1. **Velocity Change:**
- The graph starts at a velocity of 2 m/s at time $t=0$.
- The velocity decreases linearly to -16 m/s at $t=8$ seconds, indicating constant negative acceleration.
- From $t=8$ seconds to $t=26$ seconds, the velocity remains constant at -16 m/s, indicating no acceleration.
- From $t=26$ seconds to $t=36$ seconds, the velocity decreases linearly from -16 m/s to -22 m/s, indicating another period of constant negative acceleration.

2. **Key Graph Sections:**
- **0 to 8 seconds:** Linear decrease in velocity indicates constant negative acceleration. Its slope can be calculated by the change in velocity divided by the change in time: $(-16 - 2) / (8 - 0) = -18/8 = -2.25$ m/s².
- **8 to 26 seconds:** Constant velocity implies zero acceleration.
- **26 to 36 seconds:** Linear decrease in velocity from -16 m/s to -22 m/s implies another constant negative acceleration with a slope of: $(-22 - (-16)) / (36 - 26) = -6/10 = -0.6$ m/s².

**Conclusion:**

To draw the acceleration-versus-time graph:
- Plot a horizontal line at -2.25 m/s² from 0 to 8 seconds.
- A zero acceleration line from 8 to 26 seconds.
- A horizontal line at -0.6 m/s² from 26 to 36 seconds.

This representation will visually depict how acceleration changes over time at different intervals based on the given velocity data.

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