Examine the graph. velocity © 2019 StrongMind. Created using GeoGebra. The motion of a drone is modeled as velocity over time. What is the equation for this model? Select all that apply. Ov=- =-2t² + 3t4 time Ov=t²-t-2 Ov=2t²3t - 4 Ov=t² + 3t - 5

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Velocity vs. Time Graph Analysis**

**Examine the Graph:**

The graph below represents the velocity of a drone over time. It is a parabola opening upward, indicating the quadratic nature of the velocity equation.

![Velocity vs. Time Graph](graph_image_here)

- The x-axis represents time in seconds.
- The y-axis represents velocity in meters per second (m/s).
- The graph displays a symmetrical shape about its vertex, a typical characteristic of a parabolic function.

Key Points on the Graph:
- The vertex of the parabola is at (0, -5), meaning the minimum velocity is -5 m/s at time t = 0.
- The parabola intersects the time (x) axis at two points: -1 and 2.

**Question:**
What is the equation for this model of velocity over time?

**Select all that apply:**

- \( v = -2t^2 + 3t - 4 \)
- \( v = t^2 - t - 2 \)
- \( v = 2t^2 - 3t - 4 \)
- \( v = t^2 + 3t - 5 \)

To find the correct equation(s), ensure the form fits the given graph's characteristics:
1. The equation should be quadratic (in \(t^2\)).
2. The vertex should be at (0, -5).
3. The parabola should open upward.

Using this information, you can solve for the correct equation(s).
Transcribed Image Text:**Velocity vs. Time Graph Analysis** **Examine the Graph:** The graph below represents the velocity of a drone over time. It is a parabola opening upward, indicating the quadratic nature of the velocity equation. ![Velocity vs. Time Graph](graph_image_here) - The x-axis represents time in seconds. - The y-axis represents velocity in meters per second (m/s). - The graph displays a symmetrical shape about its vertex, a typical characteristic of a parabolic function. Key Points on the Graph: - The vertex of the parabola is at (0, -5), meaning the minimum velocity is -5 m/s at time t = 0. - The parabola intersects the time (x) axis at two points: -1 and 2. **Question:** What is the equation for this model of velocity over time? **Select all that apply:** - \( v = -2t^2 + 3t - 4 \) - \( v = t^2 - t - 2 \) - \( v = 2t^2 - 3t - 4 \) - \( v = t^2 + 3t - 5 \) To find the correct equation(s), ensure the form fits the given graph's characteristics: 1. The equation should be quadratic (in \(t^2\)). 2. The vertex should be at (0, -5). 3. The parabola should open upward. Using this information, you can solve for the correct equation(s).
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