Examine the graph. velocity © 2019 StrongMind. Created using GeoGebra. The motion of a drone is modeled as velocity over time. What is the equation for this model? Select all that apply. Ov=- =-2t² + 3t4 time Ov=t²-t-2 Ov=2t²3t - 4 Ov=t² + 3t - 5
Examine the graph. velocity © 2019 StrongMind. Created using GeoGebra. The motion of a drone is modeled as velocity over time. What is the equation for this model? Select all that apply. Ov=- =-2t² + 3t4 time Ov=t²-t-2 Ov=2t²3t - 4 Ov=t² + 3t - 5
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question

- The x-axis represents time in seconds.
- The y-axis represents velocity in meters per second (m/s).
- The graph displays a symmetrical shape about its vertex, a typical characteristic of a parabolic function.
Key Points on the Graph:
- The vertex of the parabola is at (0, -5), meaning the minimum velocity is -5 m/s at time t = 0.
- The parabola intersects the time (x) axis at two points: -1 and 2.
**Question:**
What is the equation for this model of velocity over time?
**Select all that apply:**
- \( v = -2t^2 + 3t - 4 \)
- \( v = t^2 - t - 2 \)
- \( v = 2t^2 - 3t - 4 \)
- \( v = t^2 + 3t - 5 \)
To find the correct equation(s), ensure the form fits the given graph's characteristics:
1. The equation should be quadratic (in \(t^2\)).
2. The vertex should be at (0, -5).
3. The parabola should open upward.
Using this information, you can solve for the correct equation(s).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6f2ab5f1-0d3c-425f-bc10-ec4282dce5ef%2F2811a332-5ab6-4517-8de8-b0092c67b89b%2Froeupti_processed.png&w=3840&q=75)
Transcribed Image Text:**Velocity vs. Time Graph Analysis**
**Examine the Graph:**
The graph below represents the velocity of a drone over time. It is a parabola opening upward, indicating the quadratic nature of the velocity equation.

- The x-axis represents time in seconds.
- The y-axis represents velocity in meters per second (m/s).
- The graph displays a symmetrical shape about its vertex, a typical characteristic of a parabolic function.
Key Points on the Graph:
- The vertex of the parabola is at (0, -5), meaning the minimum velocity is -5 m/s at time t = 0.
- The parabola intersects the time (x) axis at two points: -1 and 2.
**Question:**
What is the equation for this model of velocity over time?
**Select all that apply:**
- \( v = -2t^2 + 3t - 4 \)
- \( v = t^2 - t - 2 \)
- \( v = 2t^2 - 3t - 4 \)
- \( v = t^2 + 3t - 5 \)
To find the correct equation(s), ensure the form fits the given graph's characteristics:
1. The equation should be quadratic (in \(t^2\)).
2. The vertex should be at (0, -5).
3. The parabola should open upward.
Using this information, you can solve for the correct equation(s).
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