dq dE dE2 a x. dEx dE dEL dE b Figure 23.3 (Example 23.2) A uniformly charged ring of radius a. (a) The field at Pon the x axis due to an element of charge dq. (b) The perpendicular component of the field at Pdue to segment 1 is canceled by the perpendicular component due to segment 2. a
dq dE dE2 a x. dEx dE dEL dE b Figure 23.3 (Example 23.2) A uniformly charged ring of radius a. (a) The field at Pon the x axis due to an element of charge dq. (b) The perpendicular component of the field at Pdue to segment 1 is canceled by the perpendicular component due to segment 2. a
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter19: Electric Forces And Electric Fields
Section: Chapter Questions
Problem 18P
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Question
A ring of radius a carries a uniformly distributed positive total charge Q. Calculate the electric field due to the ring at a point P lying a distance x from its center along the central axis perpendicular to the plane of the ring (23.3a).
![dq
dE dE2
a
x.
dEx
dE
dEL
dE
b
Figure 23.3 (Example 23.2) A uniformly charged ring of radius a. (a) The field at
Pon the x axis due to an element of charge dq. (b) The perpendicular component of
the field at Pdue to segment 1 is canceled by the perpendicular component due to
segment 2.
a](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8afbf607-402e-4925-81ae-4240cd67485d%2Fc3dfa91f-5829-4a3e-9838-7df93b3185e8%2F183o05tq.png&w=3840&q=75)
Transcribed Image Text:dq
dE dE2
a
x.
dEx
dE
dEL
dE
b
Figure 23.3 (Example 23.2) A uniformly charged ring of radius a. (a) The field at
Pon the x axis due to an element of charge dq. (b) The perpendicular component of
the field at Pdue to segment 1 is canceled by the perpendicular component due to
segment 2.
a
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