### Electric Field of a Uniformly Charged DiskSuppose we have a uniformly charged disk with a radius \( R = 45.0 \) cm and a uniform charge density \( \sigma = 8.10 \times 10^{-3} \) C/m². The disk lies in the xy-plane with its center at the origin. Our goal is to find the electric field (in MN/C) due to the charged disk at various points along the z-axis.### Calculation Points and Results1. **At \( z = 5.00 \) cm**: - Electric Field: \( 24.97 \) MN/C 2. **At \( z = 10.0 \) cm**: - Electric Field: \( 47.34 \) MN/C (Incorrect result - marked with a cross) 3. **At \( z = 50.0 \) cm**: - Electric Field: \( 76.23 \) MN/C (Incorrect result - marked with a cross) 4. **At \( z = 200 \) cm**: - Electric Field: \( 10.76 \) MN/C (Incorrect result - marked with a cross)### Explanation of Graphs and DiagramsNo graphs or diagrams are present in the image. The outcome is directly given as text values for the electric field at specified z-coordinates.### SummaryWe are examining the values of the electric field at specific distances along the z-axis from the center of a charged disk. Correct values need verification or recalculations for \( z = 10.0 \) cm, \( z = 50.0 \) cm, and \( z = 200 \) cm, as the current values are marked as incorrect.Feel free to explore additional educational resources or calculations to verify and understand why specific results are marked incorrect and what the correct electric field values should be.

Answered: Image /qna-images/answer/760aa3e5-aba9-4574-8eb1-fa57a93e3b44.jpg

A uniformly charged disk with radius R = 45.0 cm and uniform charge density o = 8.10 × 10¬3 C/m² lies in the xy-plane, with its center at the origin. What is the electric field (in MN/C) due to the charged disk at the following locations? (a) z = 5.00 cm 24.97 MN/C (b) z = 10.0 cm 47.34 X MN/C (c) z = 50.0 cm 76.23 X MN/C (d) z = 200 cm 10.76 X MN/C

A uniformly charged disk with radius R = 45.0 cm and uniform charge density o = 8.10 × 10¬3 C/m² lies in the xy-plane, with its center at the origin. What is the electric field (in MN/C) due to the charged disk at the following locations? (a) z = 5.00 cm 24.97 MN/C (b) z = 10.0 cm 47.34 X MN/C (c) z = 50.0 cm 76.23 X MN/C (d) z = 200 cm 10.76 X MN/C

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

### Electric Field of a Uniformly Charged Disk

Suppose we have a uniformly charged disk with a radius \( R = 45.0 \) cm and a uniform charge density \( \sigma = 8.10 \times 10^{-3} \) C/m². The disk lies in the xy-plane with its center at the origin. Our goal is to find the electric field (in MN/C) due to the charged disk at various points along the z-axis.

### Calculation Points and Results

1. **At \( z = 5.00 \) cm**:
- Electric Field: \( 24.97 \) MN/C

2. **At \( z = 10.0 \) cm**:
- Electric Field: \( 47.34 \) MN/C (Incorrect result - marked with a cross)

3. **At \( z = 50.0 \) cm**:
- Electric Field: \( 76.23 \) MN/C (Incorrect result - marked with a cross)

4. **At \( z = 200 \) cm**:
- Electric Field: \( 10.76 \) MN/C (Incorrect result - marked with a cross)

### Explanation of Graphs and Diagrams

No graphs or diagrams are present in the image. The outcome is directly given as text values for the electric field at specified z-coordinates.

### Summary

We are examining the values of the electric field at specific distances along the z-axis from the center of a charged disk. Correct values need verification or recalculations for \( z = 10.0 \) cm, \( z = 50.0 \) cm, and \( z = 200 \) cm, as the current values are marked as incorrect.

Feel free to explore additional educational resources or calculations to verify and understand why specific results are marked incorrect and what the correct electric field values should be.

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Step 1 A) z= 5.00 cm

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Step 2 B) z= 10.00 cm

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Step 3 C) z= 50.00 cm

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Step 4 D) z= 200.00 cm

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