A uniformly charged disk with radius R = 40.0 cm and uniform charge density = 8.90 x 10-3 C/m² lies in the xy-plane, with its center at the origin. What is the electric field (in MN/C) due to the charged disk at the following locations? (a) z = 5.00 cm MN/C (b) z 10.0 cm MN/C (c) z = 50.0 cm MN/C (d) z = 200 cm MN/C

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### Problem Statement
A uniformly charged disk with radius \( R = 40.0 \) cm and uniform charge density \( \sigma = 8.90 \times 10^{-3} \) C/m² lies in the xy-plane, with its center at the origin. What is the electric field (in MN/C) due to the charged disk at the following locations?

#### (a) \( z = 5.00 \) cm
\[ \boxed{\hspace{3cm}} \text{MN/C} \]

#### (b) \( z = 10.0 \) cm
\[ \boxed{\hspace{3cm}} \text{MN/C} \]

#### (c) \( z = 50.0 \) cm
\[ \boxed{\hspace{3cm}} \text{MN/C} \]

#### (d) \( z = 200 \) cm
\[ \boxed{\hspace{3cm}} \text{MN/C} \]

### Explanation for Educational Website
This problem involves calculating the electric field generated by a uniformly charged disk at different points along the z-axis.

#### Definitions:
- **Radius (R):** The distance from the center of the disk to its edge.
- **Uniform charge density (\(\sigma\)):** Charge per unit area on the surface of the disk.
- **xy-plane:** A two-dimensional plane determined by the x-axis and y-axis.

#### Strategy:
Use the formula for the electric field due to a uniformly charged disk at a point along its perpendicular axis (the z-axis):

\[ E(z) = \frac{\sigma}{2 \epsilon_0} \left( 1 - \frac{z}{\sqrt{z^2 + R^2}} \right) \]

where:
- \( z \) is the distance from the disk along the z-axis.
- \( \epsilon_0 \) is the permittivity of free space (\( \epsilon_0 \approx 8.85 \times 10^{-12} \text{C}^2/(\text{N} \cdot \text{m}^2) \)).

#### Steps:
1. **Convert cm to m:** Ensure all distances are in meters for consistency in units.
2. **Substitute values into the formula:** Plug in the radius \( R \), charge density \( \sigma \), and distance \( z \)
Transcribed Image Text:### Problem Statement A uniformly charged disk with radius \( R = 40.0 \) cm and uniform charge density \( \sigma = 8.90 \times 10^{-3} \) C/m² lies in the xy-plane, with its center at the origin. What is the electric field (in MN/C) due to the charged disk at the following locations? #### (a) \( z = 5.00 \) cm \[ \boxed{\hspace{3cm}} \text{MN/C} \] #### (b) \( z = 10.0 \) cm \[ \boxed{\hspace{3cm}} \text{MN/C} \] #### (c) \( z = 50.0 \) cm \[ \boxed{\hspace{3cm}} \text{MN/C} \] #### (d) \( z = 200 \) cm \[ \boxed{\hspace{3cm}} \text{MN/C} \] ### Explanation for Educational Website This problem involves calculating the electric field generated by a uniformly charged disk at different points along the z-axis. #### Definitions: - **Radius (R):** The distance from the center of the disk to its edge. - **Uniform charge density (\(\sigma\)):** Charge per unit area on the surface of the disk. - **xy-plane:** A two-dimensional plane determined by the x-axis and y-axis. #### Strategy: Use the formula for the electric field due to a uniformly charged disk at a point along its perpendicular axis (the z-axis): \[ E(z) = \frac{\sigma}{2 \epsilon_0} \left( 1 - \frac{z}{\sqrt{z^2 + R^2}} \right) \] where: - \( z \) is the distance from the disk along the z-axis. - \( \epsilon_0 \) is the permittivity of free space (\( \epsilon_0 \approx 8.85 \times 10^{-12} \text{C}^2/(\text{N} \cdot \text{m}^2) \)). #### Steps: 1. **Convert cm to m:** Ensure all distances are in meters for consistency in units. 2. **Substitute values into the formula:** Plug in the radius \( R \), charge density \( \sigma \), and distance \( z \)
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