Can someone please help with question 15 Consider a simple reaction in which a reactant A forms products:A→productsWhat is the rate law if the reaction is zero order with respect to A? First order? Second order? For each case, explain how a doubling of the concentration of Awould affect the rate of reaction.Drag the appropriate items to their respective bins.ResetHelpdoubling the concentration of|A does nothing to the reaction rate= k[A]° = kdoubling the concentrationof A doubles the reaction ratedoubling the concentrationof A quadruples the reaction rateRate = k[A]' = k[A]Rate = k[A]?%3DA zero order reactionA first order reactionA second order reaction

Answered: Image /qna-images/answer/4c1b04cc-25a8-4f5e-8c79-b102301862b7.jpg

doubling the concentration of A does nothing to the reaction rate doubling the concentration of A doubles the reaction rate Rate = k[A]° = k %3D %3D Rate = k[A]' = k[A] doubling the concentration of A quadruples the reaction rate Rate = k[A]? A zero order reaction A first order reaction A second order reaction

doubling the concentration of A does nothing to the reaction rate doubling the concentration of A doubles the reaction rate Rate = k[A]° = k %3D %3D Rate = k[A]' = k[A] doubling the concentration of A quadruples the reaction rate Rate = k[A]? A zero order reaction A first order reaction A second order reaction

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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