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Doğru cevabı seçiniz. F 12 D X 0.40 m 0.45 m 0.60 m 0.60 m 1.20 m C3 0.30 m The pipe assembly shown in the figure is acted on by three couples and one force. Reduce the system to a force-couple system acting at 0. F-140 N, C₁-100 Nm, C2-180 N-m, C3-260 N.m. Ο ADF = 60% - 40j + 120k (N) ΣΜo = 198ϊ + 16j + 187k (N.m) A. BEF=61-4j-12k (N) EMo = 149.4i - 16.4j+162.7k (N.m) Ο C E F = 60% – 405 – 120k (N) ΣΜ. – –102i + 16j + 187k (N.m) - DEF=61-4j+ 12k (N) EMO = 149.4i-16.4j+162.7k (N.m) ⒸEF=60i-40j - 120k (N) ΣMo = 198i + 16j +187k (N.m) OF.EF=60i-40j +120k (N) Mo=90i+16j+ 187k (N.m)

Doğru cevabı seçiniz. F 12 D X 0.40 m 0.45 m 0.60 m 0.60 m 1.20 m C3 0.30 m The pipe assembly shown in the figure is acted on by three couples and one force. Reduce the system to a force-couple system acting at 0. F-140 N, C₁-100 Nm, C2-180 N-m, C3-260 N.m. Ο ADF = 60% - 40j + 120k (N) ΣΜo = 198ϊ + 16j + 187k (N.m) A. BEF=61-4j-12k (N) EMo = 149.4i - 16.4j+162.7k (N.m) Ο C E F = 60% – 405 – 120k (N) ΣΜ. – –102i + 16j + 187k (N.m) - DEF=61-4j+ 12k (N) EMO = 149.4i-16.4j+162.7k (N.m) ⒸEF=60i-40j - 120k (N) ΣMo = 198i + 16j +187k (N.m) OF.EF=60i-40j +120k (N) Mo=90i+16j+ 187k (N.m)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Doğru cevabı seçiniz. 121 B 0.40 m 0.45 m 1.20 m C3 0.60 m 0.60 m 0.30 m AEF=60i-40j + 120k (N) EM, 1987 + 16+ 187k (N.m) BEF=61-4j-12k (N) EMO = 149.4i-16.4j+162.7k (N.m) = Ο C E F = 60ϊ – 405 – 120k (N) ΣΜ. – –102i + 16j + 187k (N.m) D. EF = 6i- 4j+ 12k (N) EMo = 149.4i - 16.4j+ 162.7k (N.m) = The pipe assembly shown in the figure is acted on by three couples and one force. Reduce the system to a force-couple system acting at 0. F-140 N, C₁=100 N·m, C2-180 N-m, C3-260 N.m. ⒸEEF=60i-40j - 120k (N) EM, 198i + 16j +187k (N.m) Ο Ε. Σ F = 60% – 40j + 120k (N) ΣΜo = 90i + 16j + 187k (Nm) =
Transcribed Image Text:Doğru cevabı seçiniz. 121 B 0.40 m 0.45 m 1.20 m C3 0.60 m 0.60 m 0.30 m AEF=60i-40j + 120k (N) EM, 1987 + 16+ 187k (N.m) BEF=61-4j-12k (N) EMO = 149.4i-16.4j+162.7k (N.m) = Ο C E F = 60ϊ – 405 – 120k (N) ΣΜ. – –102i + 16j + 187k (N.m) D. EF = 6i- 4j+ 12k (N) EMo = 149.4i - 16.4j+ 162.7k (N.m) = The pipe assembly shown in the figure is acted on by three couples and one force. Reduce the system to a force-couple system acting at 0. F-140 N, C₁=100 N·m, C2-180 N-m, C3-260 N.m. ⒸEEF=60i-40j - 120k (N) EM, 198i + 16j +187k (N.m) Ο Ε. Σ F = 60% – 40j + 120k (N) ΣΜo = 90i + 16j + 187k (Nm) =
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