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The force system acting on the machine part is equivalent to the single force R = 475 i + 50 j acting at O. What is the value of the y-component of P? 1500 N- 240 mm 300 N 30° 120 mm 1000 N

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.8.22P: A cargo ship is tied down to marine boll arts at a number of points along its length while its cargo...

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The force system acting on the machine part is equivalent to the single force R = 475 i + 50 j acting at O. What is the value of x-component of P? 1500 N- 240 mm 300 N 30° 120 mm 1000 N
3m Find the rectangular representation of the force F, given that its magnitude 240 N. * F = -135.76 i+ 169.71 j– 101.82 k F = 135.76 i + 169.71 j+ 101.82 k F = 135.76 i - 169.71 j+ 101.82 k F = -135.76i+ 169.71 j+ 101.82 k
Consider the following coplanar system of tensile forces: F1 = 90 N at 180°, F2 = 150 N at 310° and Fy = 400 N at 0°. Use the counter clockwise direction as the positive direction of the angle from the positive x-axis. Provide the answers to 2 decimal places.
Add the following forces to find the resultant force. V1 = 150 g @ 470 V2 = 550 @ 324° V3 = 350 g @ 215° V4 = 250 @ 172° V5 = 450 g @ 285°
14. Use the same diagram for problems 14 to 19. A force F = 800 N, has its line of action in the direction from point A to point B, as shown in the figure below. Express the force F as a Cartesian vector. 2 m F- 800 N A .. 3 m 12 m •D 800 (2,9.3) (2,-9,-3) (-2,9.5) 800 A) V94 C) V94 800 B) 800 V94 (-2,9,-3) D) V94 15. Determine the components of the force F parallel to axis AD. -64 A) V94 -64 C) V94 (4,3.5) -64 B) V94 -4, 3, –5) D) 16. Determine the components of the force F perpendicular to axis AD. A) (191.43, 722.82,280.55) B) (191.43, – 722.82, –280.55) (-191.43, – 722.82, –280.55) D) (-191.43,– 722.82, 280.55) C) 17. What is the angle between OB and OD? A) 126.87° B) 127.65° C) 124.98° D) 125.84° 18. Determine the moment of the force F about point O. 800 A) M, = (12,6,-10) 800 C) M, = V94 :(-12,-6,-10) (-12,-6,10) V94 800 -10) 800 D) M, = 194 B) M, = 12,-6, 194 19. What is the moment of the force F about the axis OC? 990 A) Molloc =- (4.8.0) 960 C) Molloc = V94 890 D) Molloc = V94…
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An eyebolt is subjected to three forces as shown in the figure below. F₁-200 N F, 250 N F₁-350 N The force vector F3 in N is represented as The magnitude of the resultant force in N is -350 sin(40) i-350 cos(40) 350 sin(40) i-350 cos(40)) 350 cos(40) i-350 sin(40) j-350 cos(40) i 350 sin(40) j 596 654 498 731 Activate Wind Go to Settings to
P2 = 60 kN P1 = 25 kN P3 = 80 kN 50° y 40° 4 m 6 m A single equivalent force R can replace the three concurrent forces acting on the beam. What is the value of e in degrees?
The rectangular slab is subjected to 3 forces which are all perpendicular to the surface of the slab as shown in the figure and parameter table. Find the magnitude of the equivalent resulting force and its a and y coordinates. F3 y F1 F2 parameter value units L1 L2 L3 L4 L5 2 1 2 0.5 F1 F2 F3 2. N 3 N The magnitude of the resultant force = IN The a coordinate of the equivalent resultant force = The y coordinate of equivalent resultant force = m E E E E Z
The forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β=15° with the horizontal axis. Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=20 cm, b =33 cm and c= 65 cm, respectively. The athlete's hand is exerted by a force of F= 150 N, which makes an angle of γ=30° with the vertical from the point C. The weight of the athlete's arm is W= 100 N. The direction of application of the Fm muscle force makes an angle of α=25° with the longitudinal axis of the arm. According to this; a) Calculate the FM muscle strength. b) Calculate the angle θ of the FJ joint reaction force with the horizontal.…
Kindly show the complete step-by-step solution. I hope the picture of the asnwer will be clear. Please see the attached photo for the given problem. I will rate you with “like/upvote” after if its clear and understandable.
Two forces are applied to a hook. Variable F₁₂ Ą a b FR= d FR=( Q= B. values for the figure are given in the following table. Note the figure may not be to scale. value 75 lb 35 lb 2.5 ft B= Y = 4.5 ft 9 ft 1 ft Z a. write each force (F₁,F) as cartesian vectors. b. Find the resultant force FR express as a cartesian vector c. Find the magnitude of the resultant force FR i. a ii. B iii. Y Round your final answers to 3 significant digits/figures. Submit Question → d. Determine the coordinate direction angles of the resultant force FR lb 13/12 a degrees F₂ degrees F₁ degrees A A) lb y e) lb Alb