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Does my math add up? Calculate the moles of NaOH delivered at the equivalence point as determined by the second derivative plot for your careful trial, then enter the values in Table 2. 24.178(mL) x 1 / 1000 (mL) x 0.1002(M) = 0.0024709916 mol = 2.47 x 10 ^ -3 mol Calculate the number of moles of HCl as experimentally determined by the titration into Table 2. 2.47 x 10 ^ -3 mol Calculate the concentration of the original HCl solution for then enter the values in Table 2. M = n / VL = 2.47 x 10 ^-3 / 10 x 10 ^-3 = 0.247 molar     Table 2.  Second Derivative Processed Data   Trial 2 moles of NaOH at equivalence point 2.47 x 10 ^ -3 moles of HCl 2.47 x 10 ^ -3 concentration of original HCl solution (M)  0.247

Does my math add up? Calculate the moles of NaOH delivered at the equivalence point as determined by the second derivative plot for your careful trial, then enter the values in Table 2. 24.178(mL) x 1 / 1000 (mL) x 0.1002(M) = 0.0024709916 mol = 2.47 x 10 ^ -3 mol Calculate the number of moles of HCl as experimentally determined by the titration into Table 2. 2.47 x 10 ^ -3 mol Calculate the concentration of the original HCl solution for then enter the values in Table 2. M = n / VL = 2.47 x 10 ^-3 / 10 x 10 ^-3 = 0.247 molar     Table 2.  Second Derivative Processed Data   Trial 2 moles of NaOH at equivalence point 2.47 x 10 ^ -3 moles of HCl 2.47 x 10 ^ -3 concentration of original HCl solution (M)  0.247

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Does my math add up?

  1. Calculate the moles of NaOH delivered at the equivalence point as determined by the second derivative plot for your careful trial, then enter the values in Table 2.

24.178(mL) x 1 / 1000 (mL) x 0.1002(M) = 0.0024709916 mol

= 2.47 x 10 ^ -3 mol

  1. Calculate the number of moles of HCl as experimentally determined by the titration into Table 2.

2.47 x 10 ^ -3 mol

  1. Calculate the concentration of the original HCl solution for then enter the values in Table 2.

M = n / VL

= 2.47 x 10 ^-3 / 10 x 10 ^-3

= 0.247 molar

 

 

Table 2.  Second Derivative Processed Data

 

Trial 2

moles of NaOH at equivalence point

2.47 x 10 ^ -3

moles of HCl

2.47 x 10 ^ -3

concentration of original HCl solution (M) 

0.247
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