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Discuss the results for the physical tests briefly. Do you think the experiment was successful in synthesizing methyl salicylate?

Discuss the results for the physical tests briefly. Do you think the experiment was successful in synthesizing methyl salicylate?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Discuss the results for the physical tests briefly. Do you think the experiment was successful in synthesizing methyl salicylate?

Theoretical Yield 2.203 g Actual Yield 1.759 g Percent Yield 79.85% Reactants: 2.0 g Salicylic acid 10 mL Methanol C,H,O; + CH;OH – C;H¿O; + H,0 Calculating the limiting reactant: 2.0g C-HO, х 1 mol C-HO: 138.121 g C-H«O: 1 mol C HO, 1 mol CH0, = 0.01448005734 moi C,H;0; = 0.014 mol C;H,0; 1 moi C,H,0; + 1 mol C,H;0; Density of Methanol = 0.7913 g/mL 1 mol CH OH 138.121 g CH,OH 1 mol C H,O = 0.57 mol C,H;O; 0.7913 g CH,OH 10 mL CH;OH x 1 mI CH,OH 1 тol CH,OH According to the calculations above, Salicylic acid produces less moles of Methyl salicylate than methanol thus, it is the reactant that is completely consumed in the reaction hence, it is the limiting reagent. Calculating the theoretical yield: 0.01448005734 mol C;H3O; x 152.1494 g CH, o, 1 mol CHO, = 2.203132036 g C;H3O; 2.203 g C3HO; Calculating the Percent Yield: actual vield theoretical yisid 1.759 g CH O 2.203 g CH,O, Percent Y ield x 100 Percent Y ield x 100 = 79.85 %
Transcribed Image Text:Theoretical Yield 2.203 g Actual Yield 1.759 g Percent Yield 79.85% Reactants: 2.0 g Salicylic acid 10 mL Methanol C,H,O; + CH;OH – C;H¿O; + H,0 Calculating the limiting reactant: 2.0g C-HO, х 1 mol C-HO: 138.121 g C-H«O: 1 mol C HO, 1 mol CH0, = 0.01448005734 moi C,H;0; = 0.014 mol C;H,0; 1 moi C,H,0; + 1 mol C,H;0; Density of Methanol = 0.7913 g/mL 1 mol CH OH 138.121 g CH,OH 1 mol C H,O = 0.57 mol C,H;O; 0.7913 g CH,OH 10 mL CH;OH x 1 mI CH,OH 1 тol CH,OH According to the calculations above, Salicylic acid produces less moles of Methyl salicylate than methanol thus, it is the reactant that is completely consumed in the reaction hence, it is the limiting reagent. Calculating the theoretical yield: 0.01448005734 mol C;H3O; x 152.1494 g CH, o, 1 mol CHO, = 2.203132036 g C;H3O; 2.203 g C3HO; Calculating the Percent Yield: actual vield theoretical yisid 1.759 g CH O 2.203 g CH,O, Percent Y ield x 100 Percent Y ield x 100 = 79.85 %
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