Discuss the purposes of the following commands;subplot(3,1,1)stem(x) in Example 1 where x=[1 2 3 4]n1=-2:1 in Example 2stem(n1,x) in Example 2 s2 =s1;s1 (find n3>=min( n1 ) ) & ( n3 <=max ( ni ) )==1 ) )=x;% signal x with the duration gfQutput signal adds2 (find n3>=min ( n2 ) ) & ( n3 <=max ( n2 ))==1) )=y;% signal y with the duration ofQutput signal addadd=s1 +s2; % additionsubplot (3,1,3)stem(n3.add)title('Z=X+Y');axisLI-3 3 0 5]);Functions Used:1. min) and max() : used to find minimum and maximum value.Syntax:• mino1. min(x) -returns smallest element in an array if x is an array.-returns a row vector containing minimum element from each column if x is a matrix2. min(xy- returns an array with the same size of x and yElements of corresponding indices are checkedand minimum value isCstumadx and y must be of same length.• mex)1. max(x) -returns largest element in an array ifx is an array.-returns a row vector containing maximum element from each column if x is a matrix2. max(x)-etunS.an array with the same size of x and yElements of corresponding indices are checked and maximumvalueisCSTACnedx and y must be of same length.2. zeras) : returns a zero matrixSynatx:1. zecosla)- returns a nxn matrix of zeros.2. zeros(m.n)- returns a m xn matrix of zeros.3. zeros(mnR-) - returns amxnxp.. array fzeros3. find0 : returns the indices of non zero elements.Syntax:1. find(x) – returns the liner indices of non zero elements in an array xeg, if x= [0405 6]find(x);output : 2 4 52. find(x.n)- returns atmost first n indices of non zero element in an arrayArelationaloperatoralsobeimplementedinfind0canFor eg: find( x>10) - wil return the indices of element which are greater than 104. axis0 : used to change the attributes of the axesSyntax:1. axis([xminxmaxyminymax)- set the limits forx and y axes5.stem): Used for discrete time ploting of signalsSubtractionWith the same program code as of addition replacing arithmetic operator ' we can perform subtraction insignals. Operations on SequencesAddition can be carried out using the tsymbol and plotting will give you the result.n3>=min( n1 ) ) & ( n3 <=max ( n1 ) )==1Addition4. An array of 1 is created in the respective position which satisfies the condition eg: [111land the otherposition will be having a zero value as the s is zero matrix defined by us so that the altogether result willExample 1:be an array of 1's and O's eg: [ 1110 0]and using find function we can find the index values of the position which are 1 now and assigning thexa[1 2 3 4];subolot (3,1,1);variables of input signal there,stem(x);Say for example:xE[1 23] and s1=[0 000 0]title('x');We need s(1 2 3) =x ; ig we have to fill the first 3 position of s1 as x elements. Similarly, with the 2nd signal. Inyal1 11 1];the above condition we are making the elements of s1 equal to1where the elements of x has to be filled in soSubrlet(3,1,2);the output will be an array like this s1= [1110 0]. Now using find () function calculating the indices of thestem(y);position whose elements are equal to 1.title('Y');so that the 5(1 2 3)= x; now the elements of x will be filled in the respective position of s1.Same with the othersignalsubplot (3,1,3);The complete statement isstem(z);s1 (find n3>=min( n1 ) ) & ( n3 <=max ( n1 ) )==1 ) )=x;title('Z=X+Y');% signal x with the duration of.Qutput signalNote: In the above example index value of both the signals x and y are the same. If the indexvalues ares2 (find n3>=min ( n2 ) ) & ( n3 <=max ( n2 ))==1) )=y;% signal y with the duration gfoutput signaldifferent we have to find the range of output by comparing the index values of both signals.Step 1: After the 2 signals are defined find the duration of output signal using min & max functionsExample 2:Step 2: Initialize the signals with the duration found, else mismatch in length of the input signals error will ben1=-2:1;shown.X=[1 2 3 4];Generating a zero matrix of 1 row having elements with length = duration gfoutRutsubplot(3,1,1);• Making the length of input signals equal by making duration of both equal to that of outputstem(n);1. For making the duration of input signal equivalent to that of output we have to generate two signalstitle('X')51.52axis([-3 3 0 5]);2. s1 and s2 are generated as a zeromatrix using the zeros function having a length, equivalent to then2=0:3;duration found using min and max function earlier in Step 1yali 11 1];3. Now the next step is filling in the input elements of x and y in appropriate position of s1 and s2. For itsubplot(3,1,2);we have to find the indices corresponding to fill gut The logical statement is as follows. Here thestem(n3,x);elements satisfying the condition will be assigned 1title('Y');axis([-3 3 0 5]);n3 =min (min(n1)in( n2 ) ) : max ( max ( ni ), max ( n2 ) ); % finding the duration ofoutput signals1 =zecos(1,length (n3) );

subplot( m , n , p ) divides the current figure into an m -by- n grid and creates axes in the…

Answered: Discuss the purposes of the following…

Discuss the purposes of the following commands; subplot(3,1,1) stem(x) in Example 1 where x=[1 2 3 4] n1=-2:1 in Example 2 stem(n1,x) in Example 2

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Please show work for 18 and explanation of how you got the answer! Not an graded assignment!
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