Direction: Represent each of the following algebraically by finding its match on the box below. Let w represent the width of a rectangle. The length is 7 more than the width. 1. Four times the length is 49 2. One-fourth of the length equals 49 3. 7 cm less than twice the width is 49 4. 7 times the sum of the width and 4 cm is 49 5. Twice the width plus twice the length is 49 6. The product of the width and the length is equal to 49 4w-2-49 4w+2=49 2w-7=49 w(w+7) 4w+7=49 w+4 49 7(w+4) =49 w+7 -49 4 2w+4 2w+2(w+7) 4(w+7) =49

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Activity 2: Where's My Match
Description: This activity will enable you to translate each verbal sentence into a
mathematical equation and vice versa.
Direction: Represent each of the following algebraically by finding its match on the
box below.
Let w represent the width of a rectangle. The length is 7 more than the width.
1. Four times the length is 49
2. One-fourth of the length equals 49
3. 7 cm less than twice the width is 49
4. 7 times the sum of the width and 4 cm is 49
5. Twice the width plus twice the length is 49
6. The product of the width and the length is equal to 49
4w-2-49
4w+2=49
2w-7=49
4w+7=49
w{w+7)
w+4
49
2
7(w+4) =49
w+7
2w+4
4
2w+2(w+7)
4(w+7)
=49
Transcribed Image Text:Activity 2: Where's My Match Description: This activity will enable you to translate each verbal sentence into a mathematical equation and vice versa. Direction: Represent each of the following algebraically by finding its match on the box below. Let w represent the width of a rectangle. The length is 7 more than the width. 1. Four times the length is 49 2. One-fourth of the length equals 49 3. 7 cm less than twice the width is 49 4. 7 times the sum of the width and 4 cm is 49 5. Twice the width plus twice the length is 49 6. The product of the width and the length is equal to 49 4w-2-49 4w+2=49 2w-7=49 4w+7=49 w{w+7) w+4 49 2 7(w+4) =49 w+7 2w+4 4 2w+2(w+7) 4(w+7) =49
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