Dinitrogen tetraoxide partially decomposes according to the following equilibrium: N204(g) = 2NO2(g) A flask contains with 0.321 M of N,0g. At equilibrium at 385K, 0.153 M of N,0 remains. K, for this reaction is Write your answer to 3 significant figures.

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In a chemical equilibrium study, dinitrogen tetroxide (\( \text{N}_2\text{O}_4 \)), in the gaseous state, partially decomposes according to the equilibrium reaction:

\[ \text{N}_2\text{O}_4(\text{g}) \leftrightarrow 2\text{NO}_2(\text{g}) \]

An experiment involves a flask containing 0.321 M of \( \text{N}_2\text{O}_4 \). At equilibrium, when the temperature is 385 K, it is observed that 0.153 M of \( \text{N}_2\text{O}_4 \) remains. The task is to determine the equilibrium constant, \( K_c \), for this reaction.

The solution involves calculating \( K_c \) to three significant figures.

There are no graphs or diagrams in the image that need explanation.
Transcribed Image Text:In a chemical equilibrium study, dinitrogen tetroxide (\( \text{N}_2\text{O}_4 \)), in the gaseous state, partially decomposes according to the equilibrium reaction: \[ \text{N}_2\text{O}_4(\text{g}) \leftrightarrow 2\text{NO}_2(\text{g}) \] An experiment involves a flask containing 0.321 M of \( \text{N}_2\text{O}_4 \). At equilibrium, when the temperature is 385 K, it is observed that 0.153 M of \( \text{N}_2\text{O}_4 \) remains. The task is to determine the equilibrium constant, \( K_c \), for this reaction. The solution involves calculating \( K_c \) to three significant figures. There are no graphs or diagrams in the image that need explanation.
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