Dichloromethane, CH2Cl2 (D) and ethanol, C2H6O (E) are miscible liquids. At 25.0oC, the vapor pressure of pure D is 353. torr, and that of pure E is 56.1 torr. A solution is prepared that contains 23.3 grams of D and 79.4 grams of E. What is the vapor pressure of D (PD)? What is the vapor pressure of E (PE)?
Dichloromethane, CH2Cl2 (D) and ethanol, C2H6O (E) are miscible liquids. At 25.0oC, the vapor pressure of pure D is 353. torr, and that of pure E is 56.1 torr.
A solution is prepared that contains 23.3 grams of D and 79.4 grams of E.
- What is the vapor pressure of D (PD)?
- What is the vapor pressure of E (PE)?
Please explain the interesting numerical result you got. Why did this happen?
(d) Which of these liquids would have the higher boiling point? How do you know?
(e) How could you separate these liquids? Name the process and describe it in your own words.
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