Question1 Example 1.7 A steel har 900 mm long. Iis two endsare 40 mm and 30 mm in diameter and the length of each rodis 200 mm. The middle portion of the bar is 15 mm indiameter and 500 mm long. If the bar is suhjected an axialtensile load of 15 kN, determine (1) Stress in each section,200 x 10 N/mm²].(2) Total extension.[Take E = .%3DGiven: D, = 40 mm; D2 15 mm;D; = 30 mm;%3D%3D%3DL,= 200 mm; L2 = 500 mm; L,= 200 mm.P = 15 kN = 15 x 103 N; E= 200 x 103 N/mm2.D, = 40 mmDz- 15 mmD3- 30 mm15 KN15 KN- 200 mm500 mm L 200 mmFig. 1.5.

Answered: Image /qna-images/answer/30a62615-bb45-457b-824d-08508054db96.jpg

Answered: diameter and the length of eac portion…

diameter and the length of eac portion of the bar is 15 m ng. If the bar is subjected an etermine (1) Stress in each se [Take E = 200 x 10 N/ D, = 15 mm; D; = 30 mm- %3D L2 = 500 mm; L; 200 mm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

Question1

Example 1.7 A steel har 900 mm long. Iis two ends
are 40 mm and 30 mm in diameter and the length of each rod
is 200 mm. The middle portion of the bar is 15 mm in
diameter and 500 mm long. If the bar is suhjected an axial
tensile load of 15 kN, determine (1) Stress in each section,
200 x 10 N/mm²].
(2) Total extension.
[Take E = .
%3D
Given: D, = 40 mm; D2 15 mm;
D; = 30 mm;
%3D
%3D
%3D
L,
= 200 mm; L2 = 500 mm; L,= 200 mm.
P = 15 kN = 15 x 103 N; E= 200 x 103 N/mm2.
D, = 40 mm
Dz- 15 mm
D3- 30 mm
15 KN
15 KN
- 200 mm
500 mm L 200 mm
Fig. 1.5.

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